Answer:
volume of 2% saline (V₁) = 0.25ml
volume of water = 4.75ml
Explanation:
The requirement in the question is to obtain 0.1% of NaCl from 2% NaCl, and the process is dilution. The general dilution equation is guven by:
C₁V₁ = C₂V₂
where:
C₁ = initial concentration = 2%
V₁ = initial volume = ?
C₂ = final concentration = 0.1%
V₂ = final volume = 5ml
C₁V₁ = C₂V₂
calculating for V₁
∴ V₁ = (C₂V₂) ÷ C₁
= (0.1% × 5) ÷ 2%
V₁ = 0.25ml
Now, let us calculate the volume of water needed:
V₁ + Volume of water = V₂ (volume of 0.1% NaCl)
0.25 + volume of water = 5
volume of water = 5 - 0.25
volume of water = 4.75ml
That would be A the internet told me
Answer:
<em><u>30 units</u></em><em><u> </u></em><em><u>of </u></em><em><u>energy</u></em><em><u> </u></em><em><u>will </u></em><em><u>be </u></em><em><u>available</u></em><em><u> </u></em><em><u>to </u></em><em><u>primary</u></em><em><u> </u></em><em><u>predators.</u></em>
Explanation:
Using 10 % law i.e at each step 10 % of energy is transferred to the next trophic level at the rest of either consumed or lost to environment..
so plants have = 3000 units
herbivores = 10% of 3000 = 10/100 × 3000
= 300 units
so primary predators will have = 10% of 300
= 10/100 × 300 = 30 units
1. Sugar
2. Phosphate
3. Nitrogenous base
