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vovangra [49]
3 years ago
14

Please answer and explain these 3 questions. Thank you!

Mathematics
1 answer:
Gwar [14]3 years ago
3 0
QUESTION 1

We want to find the equation of the straight line that passes through the point
(1,24)
and has slope
m =  - 0.6


We use the point slope formula

y-y_1=m(x-x_1)

to obtain,

y - 24 =  - 0.6(x - 1)


We multiply through by 10 to get,


10y - 240 =  - 6(x - 1)


We expand bracket to get,

10y - 240 =  - 6x + 6


We group the constants on the right hand side to get,


10y + 6x = 6 + 240


we simplify to get,

10y + 6x = 246

Divide through by 2,


5y + 3x = 123

or

3x + 5y = 123

The correct answer is H.



QUESTION 2


We want to find the equation of a line that passes through
(6,-8)
with slope
m = 0

We apply the point slope formula


y-y_1=m(x-x_1)


to obtain,


y + 8 = 0(x - 6)


y + 8 = 0


y =  - 8

The correct answer is J.


QUESTION 3


We want to find the equation of the straight line that passes through,

(4,-8)

and has slope

m =  \frac{1}{4}


We apply the point-slope formula


y-y_1=m(x-x_1)


to obtain,



y + 8 =  \frac{1}{4} (x - 4)


Let us multiply through by 4 to get,


4y + 32 = x - 4
We group the constant terms on the right hand side to obtain,

4y - x =  - 4 - 32

This simplifies to,

4y - x =  - 36

We multiply through by -1 to get,


x - 4y = 36

The correct answer is A.
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