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Harman [31]
3 years ago
13

The chart shows rate of decay. A 3 column table with 7 rows. The first column is Half-lives elapsed, with entries 0, 1, 2, 3, 4,

5, 6. Second column is Fraction remaining, with entries StartFraction 1 over 1 EndFraction, StartFraction 1 over 2 EndFraction, StartFraction 1 over 4 EndFraction, StartFraction 1 over 8 EndFraction, StartFraction 1 over 16 EndFraction, StartFraction 1 over 32 EndFraction, StartFraction 1 over 64 EndFraction. Third column is Perentage remaining, with entries 100, 50, 25, 12. 5, 6. 25, 3. 125, 1. 563. Which value is being measured in the columns labeled "Fraction remaining" and "Percentage remaining"? years of decay quantity of energy number of stable atoms amount of material that has not decayed.
Mathematics
1 answer:
Morgarella [4.7K]3 years ago
8 0

The value that is being measured in the columns labeled "Fraction remaining" and "Percentage remaining" is (d) amount of material that has not decayed.

From the question, we understand that the chart measures the rate of decay.

<h3 /><h3>Fraction Remaining</h3>

So, the fraction remaining column would show the remaining amount of the material that is being measured, as a fraction.

<h3>Percentage Remaining</h3>

The percentage remaining column would show the remaining amount of the material that is being measured, as a percentage.

Hence, the value that is being measured in these columns is (d) amount of material that has not decayed.

Read more about decay rates at:

brainly.com/question/3072599

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Answer:

Adult Tickets: 173

Student Tickets: 43

Explanation:

  • To solve this problem, you'll need to set up a system of equations.
  • Assume a = # of adult tickets sold
  • Assume s = # of student tickets sold

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2: <<As the total number of tickets sold from both sides is equal to 216>>

1: <<Each adults ticket (a) costs $10.25 and each student ticket (s) costs $8, and the total amount of money earned (2117.25) from sales is the combination of these two))>>

  • Note that there are two ways to solve systems of equations (by elimnation and substitution), in this case I'll use elimnation as substitution requires one of the variables in one of the two equations to be isolated.

  • In this case, I'll elimnate a.

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  • In order to elimnate a, it has to be equal to - 10.25 so that it cancels out + 10.25 (so you have to multiply everything on the first equation by 10.25 ((what you do to one part, you'll do to all the other parts)).

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-2.25s/-2.25 = -96.75/-2.25

s = 43

  • You could solve for a using this same method, but it's easier to use the first formula <<a+s=216>> to find a.

a + 43 = 216

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3 years ago
Explain how you can use partial quotients to divide 7,563 ÷ 4 = ________.
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1890.75

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 _1_8_90_7__0__

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