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Harman [31]
2 years ago
13

The chart shows rate of decay. A 3 column table with 7 rows. The first column is Half-lives elapsed, with entries 0, 1, 2, 3, 4,

5, 6. Second column is Fraction remaining, with entries StartFraction 1 over 1 EndFraction, StartFraction 1 over 2 EndFraction, StartFraction 1 over 4 EndFraction, StartFraction 1 over 8 EndFraction, StartFraction 1 over 16 EndFraction, StartFraction 1 over 32 EndFraction, StartFraction 1 over 64 EndFraction. Third column is Perentage remaining, with entries 100, 50, 25, 12. 5, 6. 25, 3. 125, 1. 563. Which value is being measured in the columns labeled "Fraction remaining" and "Percentage remaining"? years of decay quantity of energy number of stable atoms amount of material that has not decayed.
Mathematics
1 answer:
Morgarella [4.7K]2 years ago
8 0

The value that is being measured in the columns labeled "Fraction remaining" and "Percentage remaining" is (d) amount of material that has not decayed.

From the question, we understand that the chart measures the rate of decay.

<h3 /><h3>Fraction Remaining</h3>

So, the fraction remaining column would show the remaining amount of the material that is being measured, as a fraction.

<h3>Percentage Remaining</h3>

The percentage remaining column would show the remaining amount of the material that is being measured, as a percentage.

Hence, the value that is being measured in these columns is (d) amount of material that has not decayed.

Read more about decay rates at:

brainly.com/question/3072599

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A force of 3 pounds is required to hold a spring stretched 0.6 feet beyond its natural length. how much work (in foot-pounds) is
ioda

The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound

<h3>Data obtained from the question</h3>

From the question given above, the following data were obtained:

  • Force (F) = 3 pounds
  • Extension (e) = 0.6 feet
  • Work done (Wd) =?

<h3>How to determine the spring constant</h3>
  • Force (F) = 3 pounds
  • Extension (e) = 0.6 feet
  • Spring constant (K) =?

F = Ke

Divide both sides by e

K = F/ e

K = 3 / 0.6

K = 5 pound/foot

Thus, the spring constant of the spring is 5 pound/foot

<h3>How to determine the work done</h3>
  • Spring constant (K) = 5 pound/foot
  • Extention (e) = 0.7 feet
  • Work done (Wd) =?

Wd = ½Ke²

Wd = ½ × 5 × 0.7²

Wd = 2.5 × 0.49

Wd = 1.23 foot-pound

Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound

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