Answer:
Adult Tickets: 173
Student Tickets: 43
Explanation:
- To solve this problem, you'll need to set up a system of equations.
- Assume a = # of adult tickets sold
- Assume s = # of student tickets sold
2: a + s = 216; 1: 10.25a+ 8s= 2117.25
2: <<As the total number of tickets sold from both sides is equal to 216>>
1: <<Each adults ticket (a) costs $10.25 and each student ticket (s) costs $8, and the total amount of money earned (2117.25) from sales is the combination of these two))>>
- Note that there are two ways to solve systems of equations (by elimnation and substitution), in this case I'll use elimnation as substitution requires one of the variables in one of the two equations to be isolated.
- In this case, I'll elimnate a.
a + s = 216
10.25a + 8s = 2117.25
- In order to elimnate a, it has to be equal to - 10.25 so that it cancels out + 10.25 (so you have to multiply everything on the first equation by 10.25 ((what you do to one part, you'll do to all the other parts)).
-10.25a -10.25s = -2214
10.25a + 8s = 2117.25
- a cancels, and now you solve accordingly.
-2.25s/-2.25 = -96.75/-2.25
s = 43
- You could solve for a using this same method, but it's easier to use the first formula <<a+s=216>> to find a.
a + 43 = 216
- 43 -43
a = 173
Answer:
1890.75
Step-by-step explanation:
_1_8_90_7__0__
4)7,563.0
-4
________
35
-32
_____
36
-36
_____
03
-0
______-
30
_28
_____
20
-20
______
0
1
x 4
= 4
2
x 4
= 8
3
x 4 = 12
4
x 4
= 16
5
x 4
= 20
6
x
4
= 2
7
x 4
= 28
8
x 4
= 32
9
x 4
= 36
Answer:
Ok so the first one is right and the second one is right for the first question
For the second Question your also right
Step-by-step explanation:
Question 3
12/7 is greater than 6/13 and it's asking what numbers would be incorrect meaning less than 6/13 (unmark 12/7)
1/10 is correct since 6/13 is greater than 3 / 65 (It's what you get when you multiple 1/10 with 6/13)
Unmark 4/3
Unmark 3
and 13/13 is just equal to 6/13 (leave unmarked)
Question 4
I don't know kiddo it's been a while
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It is possible. You can have the same angle measurements and different side lengths. Making it a different triangle.