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PtichkaEL [24]
3 years ago
6

If the ordered pairs graphed are all equivalent ratios, what ordered pair is missing?

Mathematics
2 answers:
Usimov [2.4K]3 years ago
7 0
I DO NOT SEE AN ANSWER
kondor19780726 [428]3 years ago
7 0

Answer:

D (4,6)

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  Please have a look at the attached photo.

<em>If the ordered pairs graphed are all equivalent ratios, what ordered pair is missing? </em>

<em>A) (3,4) </em>

<em>B) (3,6) </em>

<em>C) (4,4) </em>

<em>D) (4,6)</em>

My answer:

The given points in the graph are:

  • (2,3)
  • (6,9)
  • (8,12)

All of them have the same ratio: x : y = 2: 3

So Only answer D (4,6) has that ratio between their coordinates. We choose D.

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Answer:

-4(3+x)

Step-by-step explanation:

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What is the amount of interest earned with a deposit of 7,000 at 6.5% for 120 days
aev [14]
The interest figure always means the interest for a year.

120 days is 1/3 of a year, so you'll only earn 1/3 of 6.5% .

6.5%  =  0.065

1/3 of that is 0.02167 .

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Solve the following equation for the unknown quantity: 12x-8=3x+10. a. x=4 b. =2 c =12 d. x=1/2
dezoksy [38]

Answer:

b. x=2

Step-by-step explanation:

Step 1- Move the variable to one side.

12x-8= 3x+10

-3x     -3x

9x-8= 10

Step 2- Add 8 to both sides.

9x-8= 10

  +8   +8

9x= 18

Step 3- Divide to both sides.

<u>9x</u>= <u>18</u>

9     9

x= 2

5 0
3 years ago
If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle
stira [4]

Answer:

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<u>Step-by-step explanation:</u>

Given points end  Points are p(-3,-2) and q( 1,6)

<em>The distance of two points formula</em>

P Q = \sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2}   }

P Q = \sqrt{1 - (-3)^{2} + ((6 -(-2))^{2}   }

P Q = \sqrt{16+64} = \sqrt{80}

<em>The diameter 'd' = 2 r</em>

                       2 r = √80

                            = \sqrt{16 X 5}

                           = 4 \sqrt{5}

                     <em> r =  2√5</em>

<em>Mid-point of two end points </em>

<em>                        </em>(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )<em></em>

<em>                                               = (-1 ,2)</em>

<em>Mid-point of two end points = center of the circle</em>

<em>                                     (h,k) = (-1 , 2)</em>

                 

The equation of the circle

           (x -h )² +(y-k)² = r²

<em>          (x -(-1) )² +(y-(2))² = (2(√5))²</em>

<em>         x² + 2 x + 1 + y² - 4 y + 4 = 20</em>

<em>          x² + 2 x + y² - 4 y  = 20 -5</em>

<em>           x² + 2 x + y² - 4 y  = 15</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<em>                  </em>

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There are two methods for determining the minimum value of a quadratic equation. Each of them can be useful in determining the minimum.

(1) By plotting graph

We can find the minimum value visually by graphing the equation and finding the minimum point on the graph. The y-value of the vertex of the graph will be the minimum.

(2) By solving equation

The second way to find the minimum value comes when we have the equation y = ax² + bx + c.

If our equation is in the form y = ax^2 + bx + c, you can find the minimum by using the equation min = c - b²/4a.

The first step is to determine whether your equation gives a maximum or minimum. This can be done by looking at the x² term.

If this term is positive, the vertex point will be a minimum; if it is negative, the vertex will be a maximum.

After determining that we actually will have a minimum point, use the equation to find it.

6 0
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