Answer:
Step-by-step explanation:
What's the question?
solve for by simplifying both sides of the equation, then isolation the variable.
r = 0
:)))
Answer:
do you mean how old is lucy if so then lucy is 53 i think
Answer:
a) v(t) = 14-2t.
b) The particle is moving in a positive direction in the interval [0,7) and it's moving a negative direction in the interval
c) the particles changes direction at t=7.
Step-by-step explanation:
Recall that . We will assume that whenever its velocity is positive, it is moving in a positive direction and that whenever the velocity is negative, it is moving in a negative direction. We know that the particle changes direction when the velocity passes from positive to negative or viceversa, as t goes by.
To calculate the velocity (t), we will derivate s(t) with respect to t. Recall that given a functio of the form its derivative is . Thus, using the properties of derivatives we get that
.
We can see that 14-2t>0 if 14>2t which is equivalent that 7>t. So the particle moves in a positive direction whenever . On the same way, 14-2t<0 when t>7 ( and it changes direction at t=7 since it passes from positive to negative.
You subtract 3 with eleven and you're left with -2x>8 and then I think you divide them but I'm not 100% sure