1) 4(8p^2-3qr)<br>2) 2(-10uv+25uw^2)<br>Please answer

The crosssectional areas of triangular prism and a night cylinder are congruent. The triangular prism has a helght of 5 units, a

dmitriy555 [2]

Answer:

The volume of the triangular prism is not equal to the volume of the cylinder

Step-by-step explanation:

Given that:

The cross sectional area of triangular prism and a night cylinder are congruent. The term 'congruent' means when two objects or shapes are placed above each other , they should both overlap exactly.

It was given that:

The triangular prism has a height of 5 units

and the right cylinder height of 3 units

The conclusion that can be drawn from this is that:

The volume of the triangular prism is not equal to the volume of the cylinder.

This is because, they do not occur in the same family. A triangular prism is a three - dimensional shape that has identical, parallel ends and parallel faces.

A triangular prism has two triangles at it ends and three rectangular faces.

The volume of the triangular prism is calculate by using the formula:

$V= \dfrac{1}{2}\times b \times h\times l$

On the other hand, a cylinder is a shape with two circular ends and a curved surface.The two circular ends are congruent and both circular end posses the same cross section from one end to the other in the cylinder.

The volume of a cylinder is calculated by using the formula:

V = πr²h

Thus, we conclude that irrespective of the nature of their congruency, since the heights are different which will definitely affects their volume, the the volume of the triangular prism is not equal to the volume of the cylinder.

3 0

3 years ago

Is a parroleogram a rombus

Pie

Answer:yes

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Create a linear function that has a solution at (-2,6)

xenn [34]

(x,y) so you start at the orgin and go down two because it's negative. then you go right six and plot your point.

negative number - down or left

positive number - up or right

8 0

4 years ago

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Multiple-choice questions each have four possible answers left parenthesis a , b , c , d right (a, b, c, d), one of which is co

arlik [135]

A) Since there are four multiple choice questions Which has one correct answer. The probability of choosing a correct answer is

$P(C) = \frac{1}{4}$

The probability of choosing wrong answer is

$P(W) = \frac{3}{4}$

Using the multiplication rule
$P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}$

b) If you guess answers to three of the questions, then the possibilities of getting one correct answer are:

Either the first two are wrong and the third one is correct. This will give the arrangement;

$WWC$

Or the first is wrong the second one is correct and the last one is wrong. This will give the arrangement,

$WCW$

Or the first one is correct and the last two are wrong. This will give the arrangement,

$CWW$
.

$P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}$

$P(WCW ) = P(W) \times P( C ) \times P(W) \\ \\ P(WCW) = \frac{3}{4} \times \frac{1}{4} \times \frac{3}{4} \\ \\ P(WCW) = \frac{9}{64}$

$P(CWW ) = P(W) \times P( C ) \times P(W) \\ \\ P(CWW) = \frac{1}{4} \times \frac{3}{4} \times \frac{3}{4} \\ \\ P(CWW) = \frac{9}{64}$

c) The probability of getting one correct answer is either the first one is correct or second is correct or third is correct.

$P(One \: Correct)= P(CWW) \: or P(WCW) \: or \: P(WWC) \\ \\ P(One \: Correct)= P(CWW) \: + P(WCW) \: + \: P(WWC) \\ \\ P(One \: Correct)= \frac{9}{64} + \frac{9}{64} + \frac{9}{64} \\ \\ P(One \: Correct) = \frac{27}{64}$

7 0

4 years ago

Read 2 more answers

5-4+7x+1=_x+_ For No Solution, One solution, and Infinitely many solutions

gavmur [86]

7x+2 I'm not sure what solution it is though sorry

5 0

3 years ago

1) 4(8p^2-3qr)2) 2(-10uv+25uw^2)Please answer