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AleksAgata [21]
4 years ago
12

How can you find the volume of this aquarium

Mathematics
2 answers:
forsale [732]4 years ago
7 0

Answer:

Volume = Length times width times height

Step-by-step explanation:

If the aquarium is a rectangle just plug the numbers into the formula above.

iVinArrow [24]4 years ago
7 0
Volume= l•h•w, just plug the number in and you will get the answer:)
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Express the complex number in trigonometric form. square root of 3+2i
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\bf \begin{array}{llll}
\sqrt{3}&,&2i\\
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\end{array}\implies r[cos(\theta )+i\ sin(\theta )]\qquad 
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r=\sqrt{a^2+b^2}\\
\theta =tan^{-1}\left( \frac{b}{a} \right)
\end{cases}
\\\\\\
r=\sqrt{(\sqrt{3})^2+(2)^2}\implies r=\sqrt{3+4}\implies r=\sqrt{7}
\\\\\\
\theta =tan^{-1}\left( \frac{2}{\sqrt{3}} \right)\implies \theta \approx 49.10660535^o\textit{ or just 49 rounded up}\\\\
-------------------------------\\\\
\sqrt{3},2i\implies \sqrt{7}[cos(49^o)+i\ sin(49^o)]
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3 years ago
ANSWER ASAP CORRECT ANSWER WILL GET BRAINLIEST PLUS 78 POINTS
tino4ka555 [31]

9514 1404 393

Answer:

  C)  462

Step-by-step explanation:

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If the teacher were concerned about the order of the presentations, the number of possibilities goes up to 11P6 = 332,640 different ways.

8 0
3 years ago
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Ivenika [448]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
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8. Community Hospital, aa 120 bed facility reported that in March there were 545 discharges. Using the direct formula, what was
Anna007 [38]

Answer:

Therefore, the bed turnover rate for March was 4.5416.

Step-by-step explanation:

We know that community hospital a 120 bed facility reported that in March there were 545 discharges. We calculate what was the bed turnover rate for March.

The Direct Variation Formula is y=kx.

We know that y=545 discharges and x=120 bed.

Therefore, we get:

y=k\cdot x\\\\545=k\cdot 120\\\\k=\frac{545}{120}\\\\k=4.5416

Therefore, the bed turnover rate for March was 4.5416.

8 0
3 years ago
Enter the correct answer in the box. Solve the quadratic equation by completing the square.
viktelen [127]

Answer:

Interpreting as: X=a-sqrt b X=a+sqrt b

Input:

X = a - sqrt(b) X = a + sqrt(b)

Alternate forms:

{a = (sqrt(b) + 1) X, a = X - sqrt(b), b = 0 ∨ X = -1}

{a = (sqrt(b) + 1) X, a + sqrt(b) = X, sqrt(b) (X + 1) = 0}

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3 years ago
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