The point of observation is 2500 m away from the foot of the building.
The angle of elevation is 4°.
We need to find the height 'h' of the building.
With respect to 4°,
2500 is the adjacent side.
'h' is the opposite side.
The trigonometric ratio associating opposite & adjacent is tan.
We have
Cross multiplying we get
h = 2500 tan4°
h= 174.82 m
Option B) is the right answer.
Answer:
49m/s
59.07 m/s
Step-by-step explanation:
Given that :
Distance (s) = 178 m
Acceleration due to gravity (a) = g(downward) = 9.8m/s²
Velocity (V) after 5 seconds ;
The initial velocity (u) = 0
Using the relation :
v = u + at
Where ; t = Time = 5 seconds ; a = 9.8m/s²
v = 0 + 9.8(5)
v = 0 + 49
V = 49 m/s
Hence, velocity after 5 seconds = 49m/s
b) How fast is the ball traveling when it hits the ground?
V² = u² + 2as
Where s = height = 178m
V² = 0 + 2(9.8)(178)
V² = 0 + 3488.8
V² = 3488.8
V = √3488.8
V = 59.07 m/s
F(a+h)=2(a+h)³=2(a³+3a²h+3h²a+h³)
the second choice is the correct answer.
Answer:
Second choice, 3
Step-by-step explanation:
a^2 + b^2 = c^2
4^2 + b^2 = 5^2
16 + b^2 = 25
b^2 = 9 (square root both sides)
b = 3
Answer:
x = 89
Step-by-step explanation:
106 - 17 = 89
