Answer:
1 l 0 0 5 5 5
2 l
3 l 7
4 l
5 l
6 l 5
7 l 0
8 l 68
9 l
Step-by-step explanation:
1 l 0 0 5 5 5 =10,10,15,15,15
And so on.
Answer: Choice B. sqrt(2)
Draw out a right triangle in quadrant IV as you see in the attached image below. The horizontal and vertical legs are both 1 unit long. To ensure that the signs are properly set up, I am making the vertical leg BC have a label "-1" to mean this is below the x axis. Note how
tan(theta) = opposite/adjacent = BC/AB = -1/1 = -1
Use the pythagorean theorem to find that the hypotenuse AC is sqrt(2) units long
a^2 + b^2 = c^2
(1)^2 + (1)^2 = c^2
2 = c^2
c^2 = 2
c = sqrt(2)
The secant of theta is the ratio of the hypotenuse over the adjacent side, so we end up with
sec(theta) = hypotenuse/adjacent
sec(theta) = AC/AB
sec(theta) = sqrt(2)/1
sec(theta) = sqrt(2) which is why choice B is the answer
Answer: 72
Step-by-step explanation:
just did it
Answer:
1/4
Step-by-step explanation:
1/6 + 1/12 = 1/4