All categories

3 years ago

Pleaaseeee help me :/

Mathematics

1 answer:

Sav [38]3 years ago

8 0

Hello,

$\sqrt{x} - \sqrt{y} = (\sqrt[4]{x}+ \sqrt[4]{y} )( \sqrt[4]{x} - \sqrt[4]{y} )=72\\\\
\sqrt[4]{x}- \sqrt[4]{y}=6\\\\
(\sqrt[4]{x}+ \sqrt[4]{y})*6=72\\\\
\sqrt[4]{x}+ \sqrt[4]{y}=12 \\ 
\sqrt[4]{x}- \sqrt[4]{y}=6 \\\\
2 \sqrt[4]{x}=18==\textgreater\sqrt[4]{x}=9==\textgreater\ x=6561\\
2 \sqrt[4]{y}=6==\textgreater\sqrt[4]{y}=3==\textgreater\ y=81\\


$
Proof:
$\sqrt[4]{6561} - \sqrt[4]{81} =9-3=6\\\\
 \sqrt{6561} - \sqrt{81} =81-9=72$

You might be interested in

A prairie dog left its burrow 5 feet underground and started digging deeper into the ground. It digs straight down at a constant

SpyIntel [72]

Building and solving an equation to model the situation, it is found that it takes 4 min for the prairie dog to reach 13 feet underground.

Initially, the dog is 5 feet underground.

Each minute, the dog goes 2 more feet underground.

Hence, the underground height of the dog after t seconds is given by:

$h(t) = 5 + 2t$

The time it takes for the dog to reach 13 feet underground is t for which h(t) = 13, hence:

$h(t) = 5 + 2t$

$13 = 5 + 2t$

$2t = 8$

$t = \frac{8}{2}$

$t = 4$

It takes 4 min for the prairie dog to reach 13 feet underground.

A similar problem is given at brainly.com/question/25290003

7 0

2 years ago

Mind my hand writing but I’m not sure what sign to put the “-“ or the “+” ?

Ierofanga [76]

hello!

so the answer that you put there is actually wrong and i'll tell you why and how to do it

so since you are adding the two:

-8x + 9x = x (so you got this part right)

-12 + 4 = -8 (this is where you got it wrong, -12 added 4 goes up in value to -8)

so the final answer is x - 8

i hope this helped and have a nice day!

4 0

3 years ago

Read 2 more answers

6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately 298.87.

(b) The number of years before the capital stock exceeds $100,000 is approximately 46.15 years.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ 46.15 years.

Learn more investment function here:

brainly.com/question/25300925

6 0

2 years ago

Find the smallest of two consecutive even integers if the square is 10 more than the larger

djverab [1.8K]

I think your answers are 4 and 6

7 0

3 years ago

I need help!!!!^^^^^^^^^^^^^^^^

Rashid [163]

Answer:

Step-by-step explanation:

Cat's see the pic to clearly

8 0

3 years ago