Answer:
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po
3y(2 - y) + 8y
6y - 3y^2 + 8y
-3y^2 + 14 y
The value of f⁻¹(f(58)) is 58 and the value of the function f(f(5)) is 11
<h3>How to solve the function values?</h3>
As a general rule, we have:
f⁻¹(f(x)) = x
Substitute 58 for x
So, we have:
f⁻¹(f(58)) = 58
Hence, the value of f⁻¹(f(58)) is 58
Also, we have:
f(f(5))
From the table, we have:
f(5) = 9
So, we have:
f(f(5)) = f(9)
From the table, we have:
f(9) = 11
So, we have:
f(f(5)) = 11
Hence, the value of the function f(f(5)) is 11
Read more about invertible function at:
brainly.com/question/14391067
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Answer: Dividing two fractions is the same as multiplying the first fraction by the reciprocal of the second fraction. The first step to dividing fractions is to find the reciprocal (reverse the numerator and denominator) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators.
Step-by-step explanation:
Answer:
I believe the answer is 8 because 8 can go in both 64 and 40.
Step-by-step explanation:
If you divide 64 by 8 then you get 8 and if you divide 40 by 5 you also get 8.