Question

A car, initially at rest, travels 20 m in 4 s along a straight line with constant acceleration. the acceleration of the car is

Answer 1

Answer:acceleration=2.5m/s^2

Explanation:

initial velocity(u)=0

Distance(d)=20m

Time(t)=4seconds

Acceleration=a

D=uxt+(axt^2)/2

20=0+(ax4^2)/2

20=(ax4x4)/2

20=16a/2

Cross multiplying we get

20x2=16a

40=16a

Divide both sides by 16

40/16=16a/16

2.5=a

Acceleration=2.5m/s^2