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Natasha2012 [34]
3 years ago
7

Given the indices of refraction n_1 and n_2 of material 1 and material 2, respectively, rank these scenarios on the basis of the

phase shift in the refracted ray.
1) Rank from largest to smallest. To rank items as equivalent, overlap them.

a) n1,water=1.33
n2,air=1.00

b) n1,water=1.33
n2,quartz=1.46
c) n1,water=1.33
n2,diamond=2.42
d) n1,air=1.00
n2,quartz=1.46
e) n1,benzene=1.50
n2,water=1.33
f) n1,air=1.00
n2,water=1.33
2) Rank these scenarios on the basis of the phase shift in the reflected ray.
a) n1,benzene=1.50
n2,water=1.33
b) n1,air=1.00
n2,quartz=1.46
c) n1,water=1.33
n2,quartz=1.46
d) n1,water=1.33
n2,air=1.00
e) n1,water=1.33
n2,diamond=2.42
f) n1,air=1.00
n2,water=1.33
Physics
1 answer:
aniked [119]3 years ago
7 0

Answer:

a)  order of refraction is a, e, de, c , c) a f g

Explanation:

a) when lightning is refracted it must comply with the law of refraction

          .n₁ sin θ₁ = n₂ sinθ₂

          sin θ / sin δδa) when lightning is refracted it must comply with the law of refraction

          .n1 sin θ₁ = n2 sin θ ₂

          Sint θ1 / sin θ2 = n2 / n1

1 we see that the ray deviation is promotional to the ratio of the refractive indices

The order of refraction is a, e, de, c

.b) When a ray passes from a medium with less indicated refraction to a higher index the part of the reflected ray has a phase change of 180º

a) no phase change

b) reflected ray has a phase change of 180º

c) no phase change

d) no phase change

e) there is a phase change

f) these phase changeo  

1 we see that the ray deviation is promotional to the ratio of the refractive indices

The order of refraction is a, e, de, c

.b) When a ray passes from a medium with less indicated refraction to a higher index the part of the reflected ray has a phase change of 180º

a) no phase change

b) reflected ray has a phase change of 180º

c) no phase change

d) no phase change

e) there is a phase change

f) ay phase vabio

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Explanation:

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Answer:

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Explanation:

I have attached a free body diagram to depict this question.

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Now, when solving a problem like this we want to first remember that the beam is static; meaning it is not moving. From simple physics, this means that the sum of the forces in the y direction equals zero (i.e. the total downward forces equal the total upward forces)

Thus, from the diagram, the upward forces are T1 and T2 while the downward forces are Ws and Wb.

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The maximum weight of the bar will act at the centre, so distance from the Wb to left end = 1.46/2 = 0.73m

So, moments about left end;

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Answer:

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