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Sveta_85 [38]
3 years ago
8

Show all work & simplify ³√64

Mathematics
1 answer:
Assoli18 [71]3 years ago
4 0
4
-∛64 means that x³= 64
 4 x 4 x 4= 64
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This is algebra 1 math problem <br>f (×)=2/5x+10
Alina [70]
To find the inverse, interchange the variables and solve for y.

f^−1(x)=−25+5x/2
3 0
3 years ago
If y varies inversely with the square of x, and y=6 when x=4, find y when x=0.1
sergejj [24]

Answer:

9600

Step-by-step explanation:

y varies inversely with the square of x

y=k/(x^2)

for some non-zero constant k

y=6 when x=4

6=k/(4^2)

k=96

y=96/(x^2)

x=0.1

y=96/(0.1^2)

y=9600

8 0
2 years ago
What is the product of 3x+4 and 6x^{2} −5x+7?
LUCKY_DIMON [66]

(3x + 4)(6 {x}^{2}  - 5x + 7) \\  = 18 {x}^{3}  - 15 {x}^{2}  + 21x + 24 {x}^{2}  - 20x + 28 \\  = 18 {x}^{3}  + 9 {x}^{2}  + x + 28

I hope I helped you^_^

8 0
3 years ago
While researching the cost of school lunches per week across the state, you use a sample size of 45 weekly lunch prices. The sta
Drupady [299]

We assume the lunch prices we observe are drawn from a normal distribution with true mean \mu and standard deviation 0.68 in dollars.


We average n=45 samples to get \bar{x}.


The standard deviation of the average (an experiment where we collect 45 samples and average them) is the square root of n times smaller than than the standard deviation of the individual samples. We'll write


\sigma = 0.68 / \sqrt{45} = 0.101


Our goal is to come up with a confidence interval (a,b) that we can be 90% sure contains \mu.


Our interval takes the form of ( \bar{x} - z \sigma, \bar{x} + z \sigma ) as \bar{x} is our best guess at the middle of the interval. We have to find the z that gives us 90% of the area of the bell in the "middle".


Since we're given the standard deviation of the true distribution we don't need a t distribution or anything like that. n=45 is big enough (more than 30 or so) that we can substitute the normal distribution for the t distribution anyway.


Usually the questioner is nice enough to ask for a 95% confidence interval, which by the 68-95-99.7 rule is plus or minus two sigma. Here it's a bit less; we have to look it up.


With the right table or computer we find z that corresponds to a probability p=.90 the integral of the unit normal from -z to z. Unfortunately these tables come in various flavors and we have to convert the probability to suit. Sometimes that's a one sided probability from zero to z. That would be an area aka probability of 0.45 from 0 to z (the "body") or a probability of 0.05 from z to infinity (the "tail"). Often the table is the integral of the bell from -infinity to positive z, so we'd have to find p=0.95 in that table. We know that the answer would be z=2 if our original p had been 95% so we expect a number a bit less than 2, a smaller number of standard deviations to include a bit less of the probability.


We find z=1.65 in the typical table has p=.95 from -infinity to z. So our 90% confidence interval is


( \bar{x} - 1.65 (.101),  \bar{x} + 1.65 (.101) )


in other words a margin of error of


\pm 1.65(.101) = \pm 0.167 dollars


That's around plus or minus 17 cents.




3 0
3 years ago
Read 2 more answers
Which properties did Marty use?<br><br> Thank you very much!!
nadezda [96]

Answer:123

Step-by-step explanation:

5 0
3 years ago
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