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Morgarella [4.7K]
3 years ago
6

A 45 foot ladders leaning up against a building. The base of the latter is 20 feet away from the building. What is the angle of

elevation to the top of the building

Mathematics
1 answer:
Tatiana [17]3 years ago
8 0

Answer:

The angle of elevation to the top of the building is 63.61 degrees

Step-by-step explanation:

Here, we want to calculate angle of elevation to the top of the building.

For this, we need a triangle

Please check for this in the attachment.

From the diagram, we are to calculate the angle theta.

To do this, we use trigonometric identities.

Looking at what we have, we have the hypotenuse and the adjacent.

So the trigonometric identity to use is the cosine

Mathematically Cosine theta = adjacent/hypotenuse

Thus, Cos theta = 20/45

Cos theta = 0.444444444444444

Theta = Arc cos(0.444444444444444)

Theta = 63.61 degrees

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In parallelogram DEFG, DH = x + 5, HF = 2y, GH = 4x-3 and HE = 4y + 1. Find the values of x and y. The diagram is not drawn to s
GalinKa [24]
Rule: The diagonals of any parallelogram bisect each other. In other words, they cut each other in half.

This means DF is cut into two equal pieces: DH and HF.
Similarly, GE is cut into two equal pieces: GH and HE.

DH = HF
x+5 = 2y
x = 2y-5

GH = HE
4x-3 = 4y+1
4(x)-3 = 4y+1
4(2y-5)-3 = 4y+1 ... x has been replaced with 2y-5
8y-20-3 = 4y+1
8y-23 = 4y+1
8y-4y = 1+23
4y = 24
y = 6

If y = 6, then x is
x = 2y-5
x = 2(6)-5
x = 12-5
x = 7

--------------------------------------------

Answers: 
x = 7 and y = 6

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Step-by-step explanation:


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