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MariettaO [177]
4 years ago
11

What is the factored term form of 2x^3+4x^2-x

Mathematics
1 answer:
Westkost [7]4 years ago
8 0

Answer: x(2x^2+4x-1)

Step-by-step explanation:

2x³+4x²-x, first find the Greatest Common Factor (GCF), which is x. To find the GCF, look at what all the numbers have in common, and then see if it has the greatest value. Next factor out the GCF.

x(\frac{2x^3}{x} + \frac{4x^2}{x}-\frac{x}{x}  ) Simplify each term in the parentheses.

x(2x^2+4x-1)

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! :-)  

- Cutiepatutie ☺❀❤

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Answer: is b peoples i repeat people who dont

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4 0
3 years ago
if the length of the longest side of the rectangle is 20cm find the shaded area to the nearest hundredth PLEASE HELPP !
djverab [1.8K]

Answer:

150pi

Step-by-step explanation:

lets just say the two circles are 10 and 10 in diameter. so, one square is 5 radius. The square is 25pi area. so two are 50pi area. the area of the rectangle is 200, so 150pi

Please tell me if I'm wrong D:

3 0
3 years ago
Mathematics pls solve i need to check my answers bcs my teacher is sucky
Lilit [14]

If H is the circumcenter, then each of EH, FH, and GH are perpendicular bisectors of the legs BC, CD, and DB, respectively. So, for instance, EH cuts BC in half so that BE and EC have the same length.

Also, BH, CH, and DH are radii to the circumcircle of the triangle, so they all have the same length.

(1) CD = CF + FD = 2 • FD = 2 • 32 = 64

(2) CE = BE = 26

(3) HD = HC = 33

(4) GD = 1/2 • BD = 1/2 • 58 = 29

(5) By the Pythagorean theorem,

HG² + GD² = HD²

so

HG = √(33² - 29²) = 2 √(62)

(6) Similar to (5); by the Pythagorean theorem,

HF² + FD² = HD²

so

HF = √(33² - 32²) = √(65)

5 0
3 years ago
What is the maximum number of consecutive odd positive integers that can be added together before the sum exceeds $401$
salantis [7]

The maximum number of integers is 27 that can be added together before the summation of the A.P. Series exceeds 401.

According to the statement

We have a given that the maximum sum of the positive integers is 400.

And we have to find the value of n which is a maximum number of integers by which the value of sum become 400.

So, to find the value of the n we use the

A.P. Series'Summation formula

According to this,

S = n (n+1)/2

Here the value of s is 401

Then

S = n (n+1)/2

401 = n (n+1)/2

401*2 = n (n+1)

802 =n (n+1)

n (n+1) = 802

n^2 + n -802 =0

By the use of the Discriminant formula the

value of n becomes n = -28 and n = 27.

The negative value of n is neglected.

Therefore the value of n is 27.

So, The maximum number of integers is 27 that can be added together before the summation of the A.P. Series exceeds 401.

Learn more about maximum number of integers here brainly.com/question/24295771

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7 0
2 years ago
A magazine has 16 pages; 5 pages are short stories, and 6 pages are
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