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3 years ago

Please help!! which statement and reason complete the proof below?

Mathematics

1 answer:

butalik [34]3 years ago

7 0

Answer:

I this is the B ,I hope hepl you

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I really need help pls!! It’s also due really soon!!

frutty [35]

Answer:

I would say that It down by 1 unit and to the left by 4 units

Step-by-step explanation:

I´m pretty sure that is the answer because I solved a similar question like it and I got it right.

7 0

3 years ago

Please help! Will mark brainliest. The answer is 1.96 but I need to know to they got the answer.

nadya68 [22]

Here we are looking to find the critical value Z.

When alpha is 0.05:

0.05/2=.025

Using your z chart this would equal 1.96 positive or negative. Hope this helps!

3 0

3 years ago

1) Factor the expression and use the fundamental identities to simplify. There is more than one correct form of the answer.

Art [367]

Answer:

Step-by-step explanation:

1) 6 tan2x − 6 tan2x sin2x

= $6tan2x(1-sin2x)\\= 6tan2x (sin^2 x + cos^2 x -2sinx cosx)\\= 6tan2x (sinx+cosx)^2\\$

2) $\frac{3}{1+cos x} +\frac{3}{1-cosx} \\=\frac{3-cosx+3+cosx}{1-cos^2 x} \\=\frac{6}{sin^2 x} \\=6 cosec^2 x$

3) $\frac{sin^2 y}{1-cosy } =\frac{1-cos^2 y}{1-cosy }\\=1+cosy$

4) x=6cos t

So cost =x/6

$sint = \frac{\sqrt{36-x^2} }{\{6 } \\$

so -3sint

4 0

3 years ago

What is the value of the expression below when x=<br> 4?<br> 2x2 – 2x + 10

3241004551 [841]

Answer:

The correct answer is 6.

Step-by-step explanation:

2x2 – 2x + 10 <------ This is the original expression.

2x2 – 2(4) + 10 <----- Change the variable.

4 - 2(4) + 10 <------- Do the multiplication to the left.

4 - 8 + 10 = <------ Do the multiplication in the middle.

-4 + 10 = <----- Do the subtraction to the left.

6 <----- Simplify

Hope this helps! :D

4 0

3 years ago

2 minutes left, quick question:

rodikova [14]

Answer:

Step-by-step explanation

Drawing quadrilateral ABCD (in picture), I tried to prove that the triangles ABD CDB were congruent, proving that the quadrilateral was a parallelogram, however, with the terms you just described, it is impossible prove that the triangles were congruent as SSA is not a valid congruence postulate. Therefore, ABCD does not have to be a parallelogram.

6 0

3 years ago