Answer:
Step 3 they took the square root incorrectly
Step-by-step explanation:
5 ( x-2)^2 +6 = 86
Subtract 6 from each side
5 ( x-2)^2 +6 -6= 86-6
5 ( x-2)^2 = 80
Divide each side by 5
5 ( x-2)^2 /5 = 80/5
(x-2)^2 = 16
Take the square root of each side
sqrt((x-2)^2) = ±sqrt(16)
x-2 = ±4
Givens
x + y = 3
x =6 - 4y
Solution
Use the top equation to substitute for x in the second equation.
x = 3 - y
Put this result into the second given equation and solve for y
3 - y = 6 - 4y Add 4y to both sides.
3 - y + 4y = 6 Combine on the left
3 + 3y = 6 Subtract 3 from both sides
3 - 3 + 3y = 6 - 3 Combine
3y = 3 Divide by 3
3y/3 = 3/3 Combine
y = 1
=========================
x + y = 3 but y = 1
x + 1 = 3 Subtract 1 from both sides.
x + 1 - 1 =3 - 1
x = 2
Answer
x = 2
y = 1
Answer:
<h2>

</h2>
Step-by-step explanation:
g(x) = x² - 2x - 6
h(x) = 2x² - 5x + 2
To find (h-g) (-2) we must first find h - g(x)
To find h - g(x) subtract g(x) from h(x)
We have
<h3>

</h3><h3>

</h3>
To find (h-g) (-2) substitute the value of x that's - 2 into (h - g)(x) that's replace every x in (h - g)(x) by - 2
That's
<h3>

</h3>
We have the final answer as
<h3>

</h3>
Hope this helps you
No, it is impossible. Intuitively, a negative number sits at the left of 0 on the number line, and a positive number sits at the right of 0 on the number line. And a number x is greater than another number y if x sits at the right of y on the number line. So, every positive number is greater than any negative number.
Also, by definition, a positive number is greater than 0, and a negative number is smaller than zero. So, if x is positive and y is negative, you have

and since the relation of order "<" is transitive, this implies
