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snow_tiger [21]
3 years ago
5

3) There are 35 people living in poverty and 42 people not living in poverty

Mathematics
1 answer:
REY [17]3 years ago
3 0

Answer:

John is not correct

Step-by-step explanation:

<em>(Unless you meant 5:6)</em>

Make the base question into \frac{35}{42}

simplify as much as possible. I found the Greatest Common Denominator (GCF) of<em> 35</em> and <em>42</em>, which was<em> 7</em>

divide <em>35</em> and <em>42</em> by the GCF<em> (7)</em>, and you should get 5:6 as your answer.

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What is 5*5*5*5*5*5*5 in exponential notation form?
slamgirl [31]

Answer:

5⁷

Step-by-step explanation:

5*5*5*5*5*5*5

here,

count how many 5 are there - 7

so,

<u>exponential notation form:</u>

5*5*5*5*5*5*5 = 5⁷

5 0
3 years ago
Read 2 more answers
4p-10&lt;6p-8 or 10p+16&lt;9p-3
Finger [1]

Answer:

p>-1    or    p<-19

Step-by-step explanation:

4p-10<6p-8 (add 10 to each side)

4p< 6p+2 (subtract 6p from each side)

-2p<2  (divide by -2 and switch the sign)

p>-1

10p+16<9p-3 (subtract 16 from each side)

10p<9p+-19 (subtract 9p from each side)

p<-19

8 0
3 years ago
30 Points! please help!
SVEN [57.7K]

Answer:

18) 4 * 10 ^ -10

19) t ^ 9

Step-by-step explanation:

18. When multiplying in scientific notation, just multiply the regular numbers together and add the exponents for the tens.

So it'll be 40 * 10^-11

However, the beginning number should have the decimal right after the 4, not any place after (for example, it's 3.056, not 30.56 or 3056.)

To fix this, move the decimal place forward one space from 40. to 4.0, and add 1 to the -11 power.

So the answer is now 4 * 10^-10

19. When dividing exponents, if the base number is the same, you can divide. (Basically, you can not divide x^2 and y^3 because x and y aren't the same)

Since in this case it's t, you can divide.

Dividing exponents is simple: just subtract them.

14 - 5 = 9

so the answer is t ^ 9

3 0
3 years ago
The volume of a cube is 64 cubic inches. Which expression represents s, the length of a side of the cube?
BaLLatris [955]

Answer:64x64x64

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va
Burka [1]

Answer:

\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}

The polynomial is an approximation with an error less than or equals to <em>0.002652</em> for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)

with

\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}

for some c in the interval (-x, x)

In the particular case f

<em>f(x)=cos(x) </em>

<em> </em>

we have

\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)

therefore

\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0

and the polynomial approximation of T5(x) of cos(x) would be

\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}

for some c in (-x,x). So

\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}

and we must find the values of x for which

\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652

Working this inequality out, we find

\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0
3 years ago
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