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gulaghasi [49]
3 years ago
13

Simplify the expression, -2.75 +0.31 - 16-3

Mathematics
1 answer:
dalvyx [7]3 years ago
8 0

Answer:

decimal form is -21.44 and fractional form is -536/25

Step-by-step explanation:

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kap26 [50]
4/5 x 7= 28/5= 5 3/5
6 0
3 years ago
The librarian purchased 22 copies of a best-selling book for $385.66.
kow [346]

Answer:

$17.53

Step-by-step explanation:

$385.66 divided by 22 equals the how much each book cost

5 0
3 years ago
a random sample of 510 high school students has a normal distribution. The sample mean average ACT exam score was 21 with a 3.2
34kurt

Answer:

CI = 21 ± 0.365

Step-by-step explanation:

The confidence interval is:

CI = x ± SE * CV

where x is the sample mean, SE is the standard error, and CV is the critical value (either t score or z score).

Here, x = 21.

The standard error for a sample mean is:

SE = σ / √n

SE = 3.2 / √510

SE = 0.142

The critical value is looked up in a table or found with a calculator.  But first, we must find the alpha level and the critical probability.

α = 1 - 0.99 = 0.01

p* = 1 - (α/2) = 1 - (0.01/2) = 0.995

Using a calculator or a z-score table:

P(x<z) = 0.995

z = 2.576

Therefore:

CI = 21 ± 0.142 × 2.576

CI = 21 ± 0.365

Round as needed.

8 0
3 years ago
James puts $3,500 into a savings account that earns 2.5% simple interest. He does not touch that account for 3 years. What would
miskamm [114]

Given :

James puts $3,500 into a savings account that earns 2.5% simple interest.

He does not touch that account for 3 years.

To Find :

The new balance of the account be after 3 years.

Solution :

Interest on $3500 after 3 years is :

I = \dfrac{P_o\times r\times t}{100}\\\\I = \dfrac{3500\times 2.5\times 3}{100}\\\\I = \$262.5

So, new balance of the account after 3 years is $( 3500+262.5 ) = $3762.5  .

Hence, this is the required solution.

3 0
3 years ago
Given a term and the common difference, find the explicit formula.<br> 8. a(19) = 135<br> d = 15
Rasek [7]

The explicit formula is a(n) = 15(n – 10)

<u>Solution:</u>

Given, a term a(19) = 135 and common difference d = 15

We have to find the explicit formula.

Now, we know that, a(n) = a + (n – 1)d where a(n) is nth term, a is first term, d is common difference,

So, for a(19)  

\begin{array}{l}{\rightarrow a(19)=a+(19-1) 15} \\\\ {\rightarrow 135=a+18 \times 15} \\\\ {\rightarrow a=135-270} \\\\ {\rightarrow a=-135}\end{array}

Now, we know that, an explicit formula is an expression for finding the nth term,  

So, in our problem, expression for finding nth term is a + (n – 1)d  

\begin{array}{l}{\rightarrow-135+(n-1) 15} \\\\ {\rightarrow-135+15 n-15} \\\\ {\rightarrow 15 n-150} \\\\ {\rightarrow 15(n-10)}\end{array}

Hence, the explicit formula is a(n) = 15(n – 10).

7 0
3 years ago
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