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Black_prince [1.1K]
3 years ago
7

Determine the length and midpoint of the segment whose endpoints are (–15, 9) and (–4, 11).

Mathematics
2 answers:
ch4aika [34]3 years ago
6 0
(-15,9) \\
x_1=-15 \\
y_1=9 \\ \\
(-4,11) \\
x_2=-4 \\
y_2=11 \\ \\
\hbox{the length:} \\
l=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(-4+15)^2+(11-9)^2}=\\
=\sqrt{11^2+2^2}=\sqrt{121+4}=\sqrt{125}=\sqrt{25 \times 5}=5\sqrt{5} \\ \\
\hbox{the midpoint:} (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}) \\
\frac{x_1+x_2}{2}=\frac{-15-4}{2}=\frac{-19}{2}=-9.5 \\
\frac{y_1+y_2}{2}=\frac{9+11}{2}=\frac{20}{2}=10 \\
(-9.5,10)

The length of the segment is 5√5, the midpoint of the segment is (-9.5,10).
Ber [7]3 years ago
5 0

Answer:B is finna be yo answer


Step-by-step explanation: took e2020 test


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<img src="https://tex.z-dn.net/?f=n%20-%205%20%5Cleqslant%205n%20-%201" id="TexFormula1" title="n - 5 \leqslant 5n - 1" alt="n -
ANTONII [103]
Hello there!

n - 5 ≤ 5n - 1

Solve for n

Let's start by subtracting 5n from both sides

n - 5 - 5n ≤ 5n - 5n - 1

n - 5 - 5n ≤ -1

We need to transfer -5 on the other side, we can do that by adding 5 on both sides

n - 5 - 5n + 5 ≤ -1 + 5

n - 5n ≤ -4

-4n ≤ -4

Finally divide both sides by -4

-4n/-4 ≤ -4/-4

n ≥ -1   (This is the answer)!

Do you know why I changed the sign?


 A lot of students failed to remember that rules, which is:
When you are solving an inequality, if you divide both sides by a negative sign, you MUST change the symbol as well. If it was this <, it will change to this >. Got it? Cool!



I hope the steps are clear to understand. If you have questions, feel free to let me know...

As always, I am here to help!
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3 years ago
How many 3cm cubes can be put in a box 3cm long 6cm wide 12cm high?
lisov135 [29]

Answer:

8

Step-by-step explanation:

A cube is equal on all sides. Therefore the cubes must be 3cm x 3cm x 3cm. Therefore, each cube has an area of 27cm^3. The box that the cube has an area in is 3cm x 6cm x 12 cm which = 216cm^3. If you do 216cm^3/27cm^3 = 8 cubes

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2 years ago
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Answer

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Step-by-step explanation:

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Triangles DEF and D'E'F' are shown on the coordinate plane below: . . Triangle DEF and triangle D prime E prime F prime with ord
Brilliant_brown [7]
<span><u><em>The correct answer is:</em></u>
180</span>°<span> rotation.

<u><em>Explanation: </em></u>
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<u> A 90</u></span></span><u>°</u><span><span><u> rotation clockwise</u> will map coordinates (x, y) to (y, -x), negating the x-coordinate and swapping the x- and y-coordinates.

Performing either of these would leave our image with a coordinate that needs negated, as well as needing to swap the coordinates back around. 

This means we would have to perform <u>the same rotation again</u>; if we began with 90</span></span>°<span><span> clockwise, we would rotate 90 degrees clockwise again; if we began with 90</span></span>°<span><span> counter-clockwise, we would rotate 90 degrees counterclockwise again. Either way this rotates the figure a total of 180</span></span>°<span><span> and gives us the desired coordinates.</span></span>
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Step-by-step explanation:

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