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butalik [34]
3 years ago
5

Simplify the expression 3^0

Mathematics
2 answers:
lawyer [7]3 years ago
8 0

Answer:

1

Step-by-step explanation:

Any number when its write as raise to the power zero = 1

So,

{3}^{0}  = 1

hope this helps

brainliest appreciated

good luck! have a nice day!

Art [367]3 years ago
5 0

Answer:

1

Step-by-step explanation:

3^0

Any number (  besides 0) raised to the zero power is 1

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Work out the area of this circle radius 10cm take pie to be 3.142 and write down all the digest given by your calculator
Alika [10]

Answer:

314.2

Step-by-step explanation:

Area of a circle is: πr²

if radius is 10 then A = π*10² = 3.142 *100 =

314.2

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3 years ago
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After earning interest, the balance of an account is $420. The new balance is 7/6bof the original balance. Write an equation tha
puteri [66]
Well, we know that the total amount is $420, so we can already set one side of the equation. =420. Also, it said that the $420 is (equal to) 7/6b (b for balance).
Now just put it together!  7/6b=420 is your answer.

7 0
4 years ago
LMNP is a rectangle. Find the value of x and the length of each diagonal. LN= x and MP= 2x -8
loris [4]

Answer:

<h2>x = 8 (Verified) ✅</h2>

Step-by-step explanation:

If we visualize the figure, we can see that sides LN and MP are going to be parallel and of the same length.

So x = 2x - 8

Subtract x

0 = x - 8

x = 8

Check the answer

8 = 2(8) - 8

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3 0
3 years ago
Consider the function f(x) = x^3 - 7x^2 - 2x + 14
mars1129 [50]

Answer:

There are 3 zeros, which are:

x=7,\:x=-\sqrt{2},\:x=\sqrt{2}

Step-by-step explanation:

Given the function

f\left(x\right)\:=\:x^3\:-\:7x^2\:-\:2x\:+\:14

To get the zeros of f(x), set y or f(x) =0

so

0=x^3-7x^2-2x+14

as

x^3\:-\:7x^2\:-\:2x\:+\:14=\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)

so

\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)=0

Using the zero factor principle:

\mathrm{ \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

so

x-7=0\quad \mathrm{or}\quad \:x+\sqrt{2}=0\quad \mathrm{or}\quad \:x-\sqrt{2}=0

solving

x-7=0

  • x=7

x+\sqrt{2}=0

  • x=-\sqrt{2}

x-\sqrt{2}=0

  • x=\sqrt{2}

Therefore, there are 3 zeros, which are:

x=7,\:x=-\sqrt{2},\:x=\sqrt{2}

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Schach [20]
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