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a_sh-v [17]
3 years ago
7

What is

title="(x−8)(2x+3)=(3x−5)(x+4)\\" alt="(x−8)(2x+3)=(3x−5)(x+4)\\" align="absmiddle" class="latex-formula"> as a quadratic equation?
Mathematics
1 answer:
Softa [21]3 years ago
6 0

Answer:

-x^2 - 20x -4 = 0

Step-by-step explanation:

I assume you meant (x-8)(2x+3) = (3x-5)(x+4).

Perform the two indicated multiplications and then combine like terms:

2x^2 + 3x - 16x - 24 = 3x^2 + 12x - 5x - 20

Combine the x terms on each side:

2x^2 - 13x - 24 = 3x^2 + 7x - 20

Subtract 3x^2 from both sides:

-x^2 - 13x - 24 = 7x - 20

Subtract 7x from both sides:

-x^2 - 20x - 24 = -20

Add 20 to both sides:

-x^2 - 20x -4 = 0   This is the desired quadratic equation.

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luda_lava [24]

Answer:

y = 1.2x + 2

Step-by-step explanation:

slope = (8 - 2)/(5 - 0) = 6/5y-intercept = (0, 2)y = (6/5)x + 2y = 1.2x + 2

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3 years ago
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Find the value of x such that 365 based seven + 43 based x = 217 based 10.
Pepsi [2]

We need to find the base x in the following equation:

365_7+43_x=217_{10}

First, lets convert 365 from base 7 to base 10. This is given by

365_7=3\times7^2+6\times7^1+5\times7^0

where the upperindex denotes the position of eah number. This gives

\begin{gathered} 365_7=3\times49+6\times7+5\times1 \\ 365_7=147+42+5 \\ 365_7=194_{10} \end{gathered}

that is, 365 based 7 is equal to 194 bases 10.

Now, lets do the same for 43 based x. Lets convert 43 based x to base 10:

43_x=4\times x^1+3\times x^0

where again, the superindex 0 and 1 denote the position 0 and 1 in the number 43. This gives

43_x=(4x+3)_{10}

Now, we have all number in base 10. Then, our first equation can be written in base 10 as

194_{10}+(4x+3)_{10}=217_{10}

For simplicity, we can omit the 10 and get

194+4x+3=217

so, we can solve this equation for x. By combining similar terms. we have

197+4x=217

and by moving 197 to the right hand side, we obtain

\begin{gathered} 4x=217-197 \\ 4x=20 \end{gathered}

Finally, we get

\begin{gathered} x=\frac{20}{4} \\ x=5 \end{gathered}

Therefore, the solution is x=5

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Use a system of equations to solve this problem. Hunter needs 10 oz of a snack mix that is made up of seeds and dried fruit. The
motikmotik

The hunter should purchase 3 ounces of seeds and 7 ounces of dried fruit to satisfy the scenario.

<u><em>Explanation</em></u>

x= the amount of seeds and y= the amount of dried fruit.

As the hunter needs total 10 ounces of a snack mix , so the first equation will be..

x+y= 10 .....................................(1)

Now the seeds cost $1.50 per ounce and the dried fruit costs $2.50 per ounce. And the mixture costs $2.20 per ounce, so the second equation will be:

1.50x+2.50y= 2.20*10\\ \\ 1.50x+2.50y= 22.........................................(2)

According to the substitution method, we will isolate y from the first equation as y= 10- x

Now we will substitute this y= 10- x into the second equation in place of y

1.50x+2.50(10-x)= 22\\ \\ 1.50x+25-2.50x =22 \\ \\ -1.00x = 22-25 \\ \\ -1.00x= -3\\ \\ x= 3

Plugging this x=3 into the equation y= 10- x , we will get...

y= 10-3 =7

So, the hunter should purchase 3 ounces of seeds and 7 ounces of dried fruit to satisfy the scenario.

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3 years ago
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