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3 years ago

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A sail is in the form of a right triangle that is four times as high as it is wide.The sail is made from 32 square meters of mat

erial. What is its height?

1 answer:

NISA [10]3 years ago

6 0

5x/2=32

5x=64

x=12.8 (width)

4x=51.2 (length)

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There're some old video games you sell on Ebay for $6, $7 and $9. The titles include " The Pirates", "Under the sea" and "The dr

aniked [119]

Answer:

2/9

Step-by-step explanation:

We have 3 video games

I will assume that pirates have a water theme, so 2 have a water theme

That leaves 1 game with no water theme

P (no water theme) = games with no water theme/ total

=1/3

The games are 6 7 and 9 dollars

2 games are at least 7 dollars

P( at least 7 dollars) = games at least 7/ total

=2/3

P ( no water theme at least 7 dollars) = P (no water theme) * P( at least 7 dollars)

= 1/3*2/3

= 2/9

6 0

3 years ago

Read 2 more answers

Plz help asap i meean asap plzz

aleksandrvk [35]

1. 4.374
2. 52.64
3. 840.5

6 0

3 years ago

Read 2 more answers

What percent of 20 is 16?!!!<br><br>What's the answer and how do I work the problem out?!!

-Dominant- [34]

<span>16/20 is 80%.</span>

You find out by multiplying the denominator: 20 * 5 = 100

Then, you do the same to the numerator which is: 16 * 5 = x

So, x = 80%

Hope this helps! :D

7 0

3 years ago

While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem

Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, $H_0$ : p = 0.013 {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, $H_A$ : p > 0.013 {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion faulty modems= $\frac{10}{367}$ = 0.027

n = sample of modems = 367

So, <u><em>the test statistics</em></u> = $\frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }$

= 2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0

3 years ago

Select the correct location in the expression.

kogti [31]

Answer:

78

Correct term:60

Step-by-step explanation:

We are given that

$\frac{4x^4-6x^3+6x+3}{x-3}$

The quotient of this expression is given by

$4x^3+6x^2+18x+78+\frac{183}{x-3}$

We have to find the term in this expression which contains an error.

$\frac{4x^4-6x^3+6x+3}{x-3}$

The quotient of this expression is given by

$=4x^3+6x^2+18x+60$

$Dividend=Divisor\times quotient+ remainder$

Using the formula

$4x^4-6x^3+6x+3=(x-3)(4x^3+6x^2+18x+60)+\frac{183}{x-3}$

We can see that in the given expression there is 60 in place of 78.

The error in the expression of quotient is 78.

Correct term is 60.

4 0

3 years ago