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gavmur [86]
3 years ago
8

Select the correct location in the expression.

Mathematics
1 answer:
kogti [31]3 years ago
4 0

Answer:

78

Correct term:60

Step-by-step explanation:

We are given that

\frac{4x^4-6x^3+6x+3}{x-3}

The quotient of this expression is given by

4x^3+6x^2+18x+78+\frac{183}{x-3}

We have to find the term in this expression  which contains an error.

\frac{4x^4-6x^3+6x+3}{x-3}

The quotient of this expression is given by

=4x^3+6x^2+18x+60

Dividend=Divisor\times quotient+ remainder

Using the formula

4x^4-6x^3+6x+3=(x-3)(4x^3+6x^2+18x+60)+\frac{183}{x-3}

We can see that in the given expression there is 60 in place of 78.

The error in the expression of quotient is 78.

Correct term is 60.

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Answer:

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Step-by-step explanation:

Give:

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7 0
3 years ago
If f(x) varies directly with x2, and f(x) = 40 when x = 2, find the value of f(6). 36 60 120 360
pav-90 [236]
<span>The answer is 360.
f(x) varies directly with x^2 and f(2) = 40. What does that mean?</span>
<span>It means this f(x) = k* x^2. We need to find k.
For x=2, f(x) = 40, this means k* x^2 = 40. BUT, x=2.
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We just found what f(x) is: f(x) = 10x^2.
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Just replace the value of k by 10. => f(6) = 10* 6^2 = 10*36 = 360</span>
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