Hello!
We know what the base and area of the parallelogram are, but the height is still unknown. We also know that the formula for the area is:
A = bh
Meaning we multiply the base by the height to find the area. The opposite of multiplication is division, so we must divide the area by the base to find the height. (We work in the opposite way).
B = a / h
B = 700 cm² / 35 cm
B = 20
We can double check by multiplying 20 by 35, and the product should result in 700.
20 * 35 = 700
Therefore, the height of the parallelogram is 20 centimetres.
Answer:
9.0
Step-by-step explanation:
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Answer:
Simplifying
(5n + -3) + -1(-2n + 7) = 0
Reorder the terms:
(-3 + 5n) + -1(-2n + 7) = 0
Remove parenthesis around (-3 + 5n)
-3 + 5n + -1(-2n + 7) = 0
Reorder the terms:
-3 + 5n + -1(7 + -2n) = 0
-3 + 5n + (7 * -1 + -2n * -1) = 0
-3 + 5n + (-7 + 2n) = 0
Reorder the terms:
-3 + -7 + 5n + 2n = 0
Combine like terms: -3 + -7 = -10
-10 + 5n + 2n = 0
Combine like terms: 5n + 2n = 7n
-10 + 7n = 0
Solving
-10 + 7n = 0
Solving for variable 'n'.
Move all terms containing n to the left, all other terms to the right.
Add '10' to each side of the equation.
-10 + 10 + 7n = 0 + 10
Combine like terms: -10 + 10 = 0
0 + 7n = 0 + 10
7n = 0 + 10
Combine like terms: 0 + 10 = 10
7n = 10
Divide each side by '7'.
n = 1.428571429
Simplifying
n = 1.428571429
Answer:
g(0.9) ≈ -2.6
g(1.1) ≈ 0.6
For 1.1 the estimation is a bit too high and for 0.9 it is too low.
Step-by-step explanation:
For values of x near 1 we can estimate g(x) with t(x) = g'(1) (x-1) + g(1). Note that g'(1) = 1²+15 = 16, and for values near one g'(x) is increasing because x² is increasing for positive values. This means that the tangent line t(x) will be above the graph of g, and the estimates we will make are a bit too big for values at the right of 1, like 1.1, and they will be too low for values at the left like 0.9.
For 0.9, we estimate
g(0.9) ≈ 16* (-0.1) -1 = -2.6
g(1.1) ≈ 16* 0.1 -1 = 0.6
