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lord [1]
4 years ago
5

Can you please help??

Mathematics
2 answers:
NeTakaya4 years ago
6 0

38 percent.

60 percent girls= 60/100 girls

40 percent boys=40 boys

50 percent of girls is 30 girls

20percent of boys is 8

38 students out of 100 is 38 percent

34kurt4 years ago
3 0
70% of the student would walk to school
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When translating the point (5,0) 6 units up and 4 units to the right, we should get:
viva [34]

Answer:

(9,6)

Step-by-step explanation:

"Up" indicates y-axis. "Right" is horizontal motion, so x-axis. We add positive 6 to the y-value and positive 4 (since it's going to the right) to the x-value.

Hope this helps!

4 0
3 years ago
Terrance has 95 tickets saved up from the last time he went to the arcade. He is planning a trip to the arcade this weekend and
MissTica
He will have 263 tickets (d) because 12(14)+95=263
6 0
3 years ago
The equation of a parabola is given. y=1/4x^2−3x+18 What are the coordinates of the focus of the parabola?
7nadin3 [17]

Answer:

(6,10)

Step-by-step explanation:

Used a calculator

4 0
3 years ago
Simplify the following expression. 4a^-2b<br><br> A.) b/4a^2<br> B.)4b/a^2<br> C.)1/4a^b2
Sergio [31]
ANSWER

The correct answer is B

\frac{4b}{ {a}^{2} }


EXPLANATION

The given exponential expression is

4 {a}^{ - 2} b

We can rewrite this as,

4b \times  {a}^{ - 2}

We need to simplify to obtain a positive index, so we apply the following property,


{a}^{ - m}  =  \frac{1}{ {a}^{m} }

This implies that,


4b \times  {a}^{ - 2}  = 4b \times  \frac{1}{ {a}^{2} }

This will finally simplify to,

4b \times  {a}^{ - 2}  =\frac{4b}{ {a}^{2} }


Therefore the correct answer is B
6 0
3 years ago
Read 2 more answers
Suppose the names of the months of the year are placed in a hat and a name is drawn at random. (a) list the sample space for thi
ollegr [7]

(a)

The sample space is a set whose elements are all the possible outcomes for the experiment. Since we will extract one of the months of the years, the sample space is the set composed by all the 12 months:

\Omega = \{ \text{January},\ \text{February},\ldots,\text{December}\}

(b)

An event is a subset of the sample space. Events are often defined by their properties. In this example, the event E is the subset of the sample space defined as

E = \{ x \in \Omega: x \text{ starts with the letter J}\}

So, we have

E = \{\text{January},\ \text{June},\ \text{July}\}

(c)

If all outcomes have equal probability, then the probability of an event is the ratio bewteen its cardinality, and the cardinality of the whole sample space:

P(E) = \dfrac{n(E)}{n(\Omega)} = \dfrac{3}{12} = \dfrac{1}{4}

In words, since there are three months beginning with J out of 12 months, we have a probability of 3 over 12 to pick a month starting with J, which simplifies to 1 over 4.

3 0
3 years ago
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