Let, coordinate of point A' is (x,y).
Since, A' is the symmetric point A(3, 2) with respect to the line 2x + y - 12 = 0.
So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.
Now, their center is given by :

Also, product of slope will be -1 .( Since, they are parallel )

x = 2y - 1
So, 
Also, C satisfy given line :

Also,

Therefore, the symmetric points is
.
Answer:
28 yards
Step-by-step explanation:
It's perimeter so you add (6x2)+(8x2)
The x2 is because there's 2 of each side
Y^2+5y+10
To 2 Squared go together the regular y go together and then normal go together
first:76 ÷ 19/25=100
a:80 / 20 * 1 / 25 =0.16
b:80 * 5/4 =100
c:80 / 5 ÷ 1 / 4 =64
d:80 * 5/4 =100
e:80 * 4/5 =64
So I think both B and D should be the right answer