Answer:
a) 513775.5 m^3 ≈ 51.38 * 10^4 m^3
b) 256887.75 m^3 ≈ 25.69 * 10^4 m^3
Step-by-step explanation:
Given data :
Depth of pond = 2m
flow in the stream = 20 cfs = 4.8931 * 10^4 m^3/day
settling rate = 0.2 m/day
rate constant ( k )= 0.2 / 2 = 0.1 / day
steady-state removal of the solids required = 65%
<u>A) determine size of a single CSTR to achieve 65%</u>
First determine the time required to achieve this using the relation below
C =
∴ t = ![\frac{-1}{k}* ln( 1 - 0.65 )](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7Bk%7D%2A%20ln%28%201%20-%200.65%20%29)
= ( -1 / 0.1 ) * (- 1.05 ) = 10.5 day
The size of a single CSTR required = ( 4.8931*10^4 ) * (10.5 ) = 513775.5 m^3
<u>B) determine the sizes of a pair of identical CSTRs in series needed to achieve the desired removal</u>
sizes of a pair = 513775.5 / 2 = 256887.75 m^3
The answer to the question is letter c. I hope this helps you your welcome!!!
Answer:
A≈66.48
Step-by-step explanation: