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MAVERICK [17]
3 years ago
14

What is the solution to the equation 9(x − 1) = 27? (1 point) x = 2.5 x = 0.5 x = −0.5 x = −3.5

Mathematics
2 answers:
Tems11 [23]3 years ago
7 0

Step-by-step explanation:

Are you sure you wrote the answers correctly?

DIA [1.3K]3 years ago
5 0

answer: x=2.5

because i solved it on canvas

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If the area of a trapezoid is 234 square units what is the value of x
olganol [36]
h=9
A=((a+b)/2)h
234=((32+20)/2)h
234=(52/2)h
234=26h
9=h

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How do you turn -8/9 into a decimal and percent?
monitta

You need to divide the numerator by the denominator so it should be 8 divided by 9 to turn it into a percent multiply the decimal you get by 100. Hope this helps!

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On a​ map, 1 inch equals 20 miles. Two cities are 8 inches apart on the map. What is the actual distance between the​ cities?
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If 1 inch equals 20miles then 8 inches equals 20 x 8 = 160 miles.

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Please help with imaginary numbers worksheet!
mihalych1998 [28]

Problem 5

<h3>Answer:   6i</h3>

------------------

Explanation:

We have these four identities

  • i^0 = 1
  • i^1 = i
  • i^2 = -1
  • i^3 = -i

Notice how computing i^4 leads us back to 1. So i^4 = i^0. The pattern repeats every 4 terms. So we divide the exponent by 4 and look at the remainder. We ignore the quotient entirely. We can see that 28/4 = 7 remainder 0. Meaning that i^28 = i^0 = 1.

We can think of it like this if you wanted

i^28 = (i^4)^7 = 1^7 = 1

Then the sqrt(-36) becomes 6i

So overall, we end up with the final answer of 6i

=============================================

Problem 6

<h3>Answer:  -3i</h3>

------------------

Explanation:

We'll use the ideas mentioned in problem 5

46/4 = 11 remainder 2

i^46 = i^2 = -1

sqrt(-9) = 3i

The two outside negative signs cancel out, but there's still a negative from -1 we found earlier. So we end up with -3i

In other words, here is one way you could write out the steps

-i^{46}*-\sqrt{-9}\\\\-i^{2}*-3i\\\\i^{2}*3i\\\\-1*3i\\\\-3i\\\\

=============================================

Problem 7

<h3>Answer:   -1</h3>

------------------

Work Shown:

i^10 = i^2 because 10/4 = 2 remainder 2

i^19 = i^3 because 19/4 = 4 remainder 3

i^7 = i^3 because 7/4 = 1 remainder 3

Again, all we care about are the remainders.

i^{10}+i^{19} - i^{7}\\\\i^{2}+i^{3} - i^{3}\\\\i^{2}\\\\-1

=============================================

Problem 8

<h3>Answer:    -1 + i</h3>

------------------

Work Shown:

i^22*i^6 = i^(22+6) = i^28

Earlier in problem 5, we found that i^28 = i^0 = 1

So,

i^1 - \left(i^{22}*i^{6}\right)\\\\i^1 - i^{28}\\\\i^1 - i^{0}\\\\i - 1\\\\-1+i

8 0
2 years ago
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Jacinta scores 23, 19, and 27 on three of her four tests. She wants to get an
pochemuha

Answer:

23+19+27+x = 96

x > 27

not sure if the answer can be left that way or do you assume that test results are whole numbers, if so then the answer  would b=have to be 28.. but I think that >27 is the answer expected

Step-by-step explanation:

7 0
3 years ago
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