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abruzzese [7]
3 years ago
9

Which symbol gives you more information about two numerical expressions

Mathematics
1 answer:
Aloiza [94]3 years ago
7 0
You use parenthesis to tell the difference between to groups of numbers

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(x+3)^2 + 16/(x+3)^2 = 92 <br><br> x + 1/(x+3) = ??
Irina-Kira [14]
One
Remark

This is very complicate unless you pick the right method. It's very handy o know about substitutions.

Method
Let z = (k + 2)^2

Now the problem becomes
z + 16/z = 92           Multiply through by z 

Solution
z^2 + 16 = 92z
That does not look very promising. If you know the quadratic formula, this mess can be solved. If you do not know what the quadratic formula is, then what I've written is the answer. 

Worse yet, you have to know what complex numbers are. Is this something you know about? The z form of this equation is fine. It gives answers that are rational. The problem is that both are negative and so in your next step, you will be forced to take the square root of a negative number.

Maybe the answer is just
(x + 3)^ + 16 = 92(x + 3)^2
If all you have to do is expand this then you get
x^2 + 6x + 9  + 16 = 92(x^2 + 6x + 9) Remove the brackets.
x^2 + 6x + 25 = 92x^2 + 552x + 828  Put the left over to the right.
0 = 92x^2 - x^2 + 552x - 6x + 828 - 25
0 = 91x^1 + 546x + 803


It looks that way from the second question. If I'm wrong about that, put a comment down below.

Two
 Put over a common denominator and expand
\frac{(x + 3)^2 + 1}{(x + 3)^2}  =  \frac{x^2 + 6x + 9 + 1}{x^2 + 6x + 9} =  \frac{x^2 + 6x + 10}{x^2 + 6x + 9}
3 0
3 years ago
What is the measure, in degree, of angle z ?
Jobisdone [24]

Answer:

55°

Step-by-step explanation:

if the middle is straight, then x+35°=90°

7 0
3 years ago
HELPP!!
SSSSS [86.1K]

Answer:

There are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

Step-by-step explanation:

This can be obtained by after a simple counting of number from 2020 and 2400 as follows:

The first set of integers are:

2345, 2346, 2347, 2348, and 2349.

Therefore, there are 6 integers in first set.

The second set of integers are:

2356, 2357, 2358, and 2359.

Therefore, there are 4 integers in second set.

The third set of integers are:

2367, 2368, and 2369.

Therefore, there are 3 integers in third set.

The fourth set of integers are:

2378, and 2379.

Therefore, there are 2 integers in fourth set.

The fifth and the last set of integer is:

2389

Therefore, there is only 1 integers in fifth set.

Adding all the integers from each of the set above, we have:

Total number of integers = 6 + 4 + 3 + 2 + 1 = 15

Therefore, there are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

7 0
3 years ago
Question
ser-zykov [4K]

Answer:

2 jell djeeujdeieuwieue

3 0
3 years ago
Evaluate.<br><br><br><br> 2⋅((42)−1)
Nana76 [90]

Answer:

Hi there!

Your answer is:

<em />

<em>Question was unclear! See below for answer possibilities!</em>

Step-by-step explanation:

<u>IF "-1" MEANS MULTIPLY BY NEGATIVE 1</u>

2((42) -1 ))

2(-42)

<h2><em>-84</em></h2>

<u>IF "-1" MEANS SUBTRACT 1</u>

2((42)-1)

2(41)

<h2><em>82</em></h2>

Hope this helps

5 0
4 years ago
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