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abruzzese [7]
3 years ago
9

Which symbol gives you more information about two numerical expressions

Mathematics
1 answer:
Aloiza [94]3 years ago
7 0
You use parenthesis to tell the difference between to groups of numbers

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Help I don't really get this!
Fantom [35]

Answer:

ask your teacher about this wag puro asasa sa iba Kaya ka pinag aaral para matutu ka right

Step-by-step explanation:

yes

6 0
2 years ago
I really don't understand help
Zielflug [23.3K]

Answer:

128 ft sq.

Step-by-step explanation:

The way you find the area of a square is by multiplying one side by another, and since it is a square, the sides are the same. This means that if we have a square with a side length of x, the way to find the area of that square is to multiply x by x, which can be written as x^2. Now, since we're doubling this, we can say that double Mary's garden is 2 * x^2. If we substitute 8 in for x, we have to multiply 8^2 by 2 or 8 by 8 by 2 to find our answer. 8 times 8 is 64 and 64 times 2 is 128.

5 0
2 years ago
Help plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
Setler79 [48]

Answer:

diameter = 3,600 units

Step-by-step explanation:

Let \pi = 3.14

C = 2\pir

11,304 = 2(3.14)r

r = 1,800

d = 2r = 2(1,800) = 3,600

7 0
2 years ago
Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x3 and y = x. (10 points)
USPshnik [31]
See the graph attached.

The midpoint rule states that you can calculate the area under a curve by using the formula:
M_{n} = \frac{b - a}{2} [ f(\frac{x_{0} + x_{1} }{2}) +  f(\frac{x_{1} + x_{2} }{2}) + ... +  f(\frac{x_{n-1} + x_{n} }{2})]

In your case:
a = 0
b = 1
n = 4
x₀ = 0
x₁ = 1/4
x₂ = 1/2
x₃ = 3/4
x₄ = 1

Therefore, you'll have:
M_{4} = \frac{1 - 0}{4} [ f(\frac{0 +  \frac{1}{4} }{2}) +  f(\frac{ \frac{1}{4} + \frac{1}{2} }{2}) +  f(\frac{\frac{1}{2} + \frac{3}{4} }{2}) + f(\frac{\frac{3}{4} + 1} {2})]
M_{4} = \frac{1}{4} [ f(\frac{1}{8}) +  f(\frac{3}{8}) +  f(\frac{5}{8}) + f(\frac{7}{8})]

Now, to evaluate your f(x), you need to look at the graph and notice that:
f(x) = x - x³

Therefore:
M_{4} = \frac{1}{4} [(\frac{1}{8} - (\frac{1}{8})^{3}) + (\frac{3}{8} - (\frac{3}{8})^{3}) + (\frac{5}{8} - (\frac{5}{8})^{3}) + (\frac{7}{8} - (\frac{7}{8})^{3})]

M_{4} = \frac{1}{4} [(\frac{1}{8} - \frac{1}{512}) + (\frac{3}{8} - \frac{27}{512}) + (\frac{5}{8} - \frac{125}{512}) + (\frac{7}{8} - \frac{343}{512})]

M₄ = 1/4 · (2 - 478/512)
     = 0.2666

Hence, the <span>area of the region bounded by y = x³ and y = x</span> is approximately 0.267 square units.

6 0
3 years ago
Factor this completely thank you
jeka94

4(2x raise to power 2-4-7x)

3 0
2 years ago
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