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zimovet [89]
3 years ago
13

A large research hospital is considering a new computer-based training course for lab safety. The total cost of the hospital's c

urrent training program is $80,000 per year. If the new training program will reduce these costs to $60,000 per year, what is the maximum acceptable cost to initiate the program to reach the break-even point within three years? What is the return on investment for that scenario?
Mathematics
2 answers:
Katarina [22]3 years ago
8 0
I need that money to but new nikes
Neporo4naja [7]3 years ago
6 0

We have been given that total cost of the hospital's current training program is $80,000 per year.

If the new training program will reduce these costs to $60,000 per year , it will help the hospital to save $20,000 per year. So in 3 years hospital will save $60,000.

Since we know that for break-even point to occur, the savings or profit from new program should be equal to the cost of the new program.

The maximum acceptable cost to initiate the program to reach the break-even point within three years will be 3\cdot 20,000=60,000. In 3 years there will be no profit and loss so the break-even point will happen.

Therefore,the return on the investment in this scenario will be $0.

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50 POINTS
mamaluj [8]

Answer:

The answer is below

Step-by-step explanation:

The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds: A linear model with ordered pairs at 0, 60 and 2, 75 and 4, 75 and 6, 40 and 8, 20 and 10, 0 and 12, 0 and 14, 0. The x axis is labeled Time in seconds, and the y axis is labeled Height in feet. Part A: During what interval(s) of the domain is the water balloon's height increasing? (2 points) Part B: During what interval(s) of the domain is the water balloon's height staying the same? (2 points) Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest? Use complete sentences to support your answer. (3 points) Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 16 seconds.

Answer:

Part A:

Between 0 and 2 seconds, the height of the balloon increases from 60 feet to 75 feet  at a rate of 7.5 ft/s

Part B:

Between 2 and 4 seconds, the height stays constant at 75 feet.

Part C:

Between 4 and 6 seconds, the height of the balloon decreases from 75 feet to 40 feet at a rate of -17.5 ft/s

Between 6 and 8 seconds, the height of the balloon decreases from 40 feet to 20 feet at a rate of -10 ft/s

Between 8 and 10 seconds, the height of the balloon decreases from 20 feet to 0 feet at a rate of -10 ft/s

Hence it fastest decreasing rate is -17.5 ft/s which is between 4 to 6 seconds.

Part D:

From 10 seconds, the balloon is at the ground (0 feet), it continues to remain at 0 feet even at 16 seconds.

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vovangra [49]

Answer:

y = 5

z = 55

Step-by-step explanation:

90 - 35 = 55

z = 55

7y = 35

\frac{7y}{7} = \frac{35}{7}

y= 5

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1/5x8 in simplest form
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Answer:

try the calculator best thing to use

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