Answer:
(a) t = 7 sec approximately; (b) t = 6 sec
Step-by-step explanation:
(a) Set h(t)= -16(t-3)^2 + 288 = 0 and solve for t:
16(t-3)^2 = 288
After simplification, this becomes (t - 3)^2 = 18, or t - 3 = ±3√2.
Because t can be only zero or positive, t = 3 + 3√2 = 7 seconds
(b) Solve h(t)= -16(t-3)^2 + 288 = 150:
-16(t-3)^2 = - 162
or (t - 3)^2 = 10.125, or
t - 3 = ±3.18, or, finally, t = 6.18 sec (discard t = -0.18 sec)
Answer:
Step-by-step explanation:
Factor top and bottom.
The numerator is a difference of two squares, and the denominator is a quadratic.
=
=
If x does not equal -1 and does not equal 4, we can cancel the common factors in italics to give
=
=
Answer:
(C)4
Step-by-step explanation:
Given the line: 
The gradient of the line, 
A line perpendicular to the given line will have a gradient,
(by definition of perpendicularity).
Therefore, a perpendicular line that passes through the point (4,1) is:

Comparing with the slope-intercept form y=mx+x, the slope of the perpendicular line, b=4.