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Bogdan [553]
3 years ago
11

What is the range of possible sizes for x?

Mathematics
1 answer:
lutik1710 [3]3 years ago
3 0

Answer:

<em>0.5 < x < 15.5</em>

Step-by-step explanation:

<u>Triangle Inequality Theorem</u>

Let y and z be two of the side lengths of a triangle. The length of the third side x cannot be any number. It must satisfy all the following restrictions:

x + y > z

x + z > y

y + z > x

Combining the above inequalities, and provided y>z, the third size must satisfy:

y - z < x < y + z

The two side lengths given in the triangle of the figure are y=8.5, z=8.0, thus the possible values of x lie in the interval

8.5 - 8.0 < x < 8.5 + 8.0

0.5 < x < 15.5

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zimovet [89]

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Step-by-step explanation:

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First: plug 3 into g(x) = x^ (2-1)

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Next: plug 3 into f(x)= 2^(x-1)

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hodyreva [135]
BC= 39



Explanation:


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So then 3*12+3=39


And you can check by doing 39+39+48+48
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