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Mnenie [13.5K]
4 years ago
10

1/7-3 (3/7n-2/7) expand the expression and combine like terms

Mathematics
1 answer:
velikii [3]4 years ago
8 0
1/7-9/7n+6/7
1-9/7n
that is the extended form and is simplified

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A manufacturer knows that their items have a normally distributed length, with a mean of 13.1 inches, and standard deviation of
Afina-wow [57]

Answer:

0.73% probability that their mean length is less than 11.1 inches

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 13.1, \sigma = 4.1, n = 25, s = \frac{4.1}{\sqrt{25}} = 0.82

What is the probability that their mean length is less than 11.1 inches

This is the pvalue of Z when X = 11.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{11.1 - 13.1}{0.82}

Z = -2.44

Z = -2.44 has a pvalue of 0.0073.

0.73% probability that their mean length is less than 11.1 inches

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