X - the number
3x - 7 = -4 |add 7 to both sides
3x = 3 |divide both sides by 3
x = 1
x in terms of b:
-2(bx - 5) = 16
-2bx + 10 = 16
-2bx = 6
x = 6 / -2b
x = -3/b
--------------------------------
when b = 3 then
-2(3x - 5) = 16
-6x + 10 = 16
-6x = 6
x = -1
Answer
The value of x in terms of b is -3/b
The value of x when b is 3 is -1
Answer:
I think it is 9
Step-by-step explanation:
as for number one I did 5×7=35 overall and 15×21= 315
then I did 315÷35=9 which is the scale factor.
hope this is correct and help u understand:)
If the quiz is worth 50 points and each question is worth 10 that means for every question he could’ve missed would be taking away 10 from that 50. So lets say if he misses 2 questions. 2 x 10 would be 20. You take away 20 from 50 which would be: 50 - 20 = 30. And it goes on from there.
Hope that helps!
Answer:
Step-by-step explanation:
From the given information:
The uniform distribution can be represented by:
The function of the insurance is:
Hence, the variance of the insurance can also be an account forum.
![Var [I_{(x}) = E [I^2(x)] - [E(I(x)]^2](https://tex.z-dn.net/?f=Var%20%5BI_%7B%28x%7D%29%20%3D%20E%20%5BI%5E2%28x%29%5D%20-%20%5BE%28I%28x%29%5D%5E2)
here;
![E[I(x)] = \int f_x(x) I (x) \ sx](https://tex.z-dn.net/?f=E%5BI%28x%29%5D%20%3D%20%5Cint%20f_x%28x%29%20I%20%28x%29%20%5C%20sx)
![E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx](https://tex.z-dn.net/?f=E%5BI%28x%29%5D%20%3D%20%5Cdfrac%7B1%7D%7B1500%7D%20%5Cint%20%5E%7B1500%7D_%7B250%7B%20%28x-%20250%29%20%5C%20dx)
Similarly;
![E[I^2(x)] = \int f_x(x) I^2 (x) \ sx](https://tex.z-dn.net/?f=E%5BI%5E2%28x%29%5D%20%3D%20%5Cint%20f_x%28x%29%20I%5E2%20%28x%29%20%5C%20sx)
![E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250)^2 \ dx](https://tex.z-dn.net/?f=E%5BI%28x%29%5D%20%3D%20%5Cdfrac%7B1%7D%7B1500%7D%20%5Cint%20%5E%7B1500%7D_%7B250%7B%20%28x-%20250%29%5E2%20%5C%20dx)
∴
![Var {I(x)} = 1250^2 \Big [ \dfrac{5}{18} - \dfrac{25}{144}]](https://tex.z-dn.net/?f=Var%20%7BI%28x%29%7D%20%3D%201250%5E2%20%5CBig%20%5B%20%5Cdfrac%7B5%7D%7B18%7D%20-%20%5Cdfrac%7B25%7D%7B144%7D%5D)
Finally, the standard deviation of the insurance payment is:
≅ 404
