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kvv77 [185]
3 years ago
5

Answer correct for brainliest and also get a thanks ! Don't answer if you don't know it please :)

Mathematics
1 answer:
xxMikexx [17]3 years ago
7 0
Anything that is 0.7-1.0 is strong positive.

So the answer is strong positive association
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What is the square root of 18y over 36y to the third power? - I need to show work!
pochemuha
\sqrt{\dfrac{18y}{36y^3}}=\sqrt{\dfrac{18y}{18y\cdot2y^2}}=\sqrt{\dfrac{1}{2y^2}}=\dfrac{\sqrt1}{\sqrt{2y^2}}=\dfrac{1}{\sqrt2\cdot\sqrt{y^2}}=\dfrac{1}{y\sqrt2}

\dfrac{1}{y\sqrt2}=\dfrac{1}{y\sqrt2}\cdot\dfrac{\sqrt2}{\sqrt2}=\dfrac{\sqrt2}{2y}
5 0
3 years ago
Can someone please help me ASAP
Nastasia [14]

Answer:

A.

Step-by-step explanation:

First write the picture down like so:

x(8) divided by 10.9 - 7.9 then go down the row wel 10.9 x 8 = 87.2 divide that by 10.9  and youll get 8 then subtract 8 from 7.9 and you will get 0.1

6 0
3 years ago
4. The co-ordinates of the mid-point of the line joining the two given points (a, b) and ( - 7,-5) is ( 3/2,5).find(a, b).​
cestrela7 [59]

Answer:

a = 10

b = 15

Hope this is correct!!

4 0
3 years ago
A local hamburger shop sold a combined total of 575 hamburgers and cheeseburgers on Thursday.There were 75 more cheeseburgers so
STatiana [176]

Answer:

There were 250 hamburgers sold

Step-by-step explanation:

h = hamburgers

c =cheeseburgers

c+h = 575

c =75+h

c+h =575

Substituting 75+h in for c in the second equation

75+h +h =575

Combine like terms

75+2h = 575

Subtract 75 from each side

75-75 +2h = 575-75

2h = 500

Divide each side by 2

2h/2 = 500/2

h = 250

There were 250 hamburgers sold

7 0
4 years ago
Jasmine owns a jewelry store and marks up the price from the distributor to earn a profit. She buys a necklace for $100, a pair
denpristay [2]

A. Jasmine buys a necklace for $100 and wants to earn at least $40 on it but does not want to mark price by more than $80. In this case $40 is 40% {(40:100)·100%} and $80 is 80% {(80:100)·100%}. Then the range of the percent that Jasmine can mark up necklace is [40%,80%].

She also buys a pair of earrings for $130 and wants to earn at least $40 on it but does not want to mark price by more than $80. In this case $40 is nearly 31% {(40:130)·100%} and $80 is 62% {(80:130)·100%}. Then the range of the percent that Jasmine can mark up necklace is [31%,62%].

At last, she buys a ring for $160 and wants to earn at least $40 on it but does not want to mark price by more than $80. In this case $40 is nearly 25% {(40:160)·100%} and $80 is 50% {(80:160)·100%}. Then the range of the percent that Jasmine can mark up necklace is [25%,80%].

B. She should use the maximal number from the left end and the minimum number from the right end, so she should use percent from the range [40%, 50%]. If she wants to maximize her profit, she should select 50%.

C. If she mark up any price by 50%, then the price of a necklace will become $150 {(150%:100%)·100}, the price of a pair of earrings will become $195 {(150%:100%)·130} and the price of a ring will be $240 {(150%:100%)·160}.

D. She pays in total $100+$130+$160=$390. After selling these jewerlies she gets $150+$195+$240=$585. The difference is $585-$390=$195 - her total profit.

4 0
3 years ago
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