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3 years ago

Solve algebraically y = - x - 2 y = - 2x

Mathematics

1 answer:

Alchen [17]3 years ago

5 0

Solving algebraically we get x=2 and y=-4

Step-by-step explanation:

We need to solve the equations:

$y=-x-2\\y=-2x$

Solving and finding value of x and y

Let:

$y=-x-2\,\,eq(1)\\y=-2x\,\,eq(2)$

Subtract both equations

$y=-x-2\\y=-2x\\-\,\,\,\,+\\------\\0=x-2\\x=2$

Putting value of x in eq(1) and find value of y:

$y=-x-2\\y=-2-2\\y=-4$

So, value of y is -4

Solving algebraically we get x=2 and y=-4

Keywords: System of equations

Learn more about system of equations at:

#learnwithBrainly

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2 years ago

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Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

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assume

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For $C=7.85\ m$

assume

$\pi =3.14$

substitute and solve for r

$7.85=2(3.14)r$

$r=7.85/[2(3.14)]=1.25\ m$

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

$SA=4\pi r^{2}$

Find the surface area of sphere with a 5.50-meter circumference

For $r=0.88\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(0.88)^{2}$

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Find the surface area of sphere with a 7.85-meter circumference

For $r=1.25\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(1.25)^{2}$

$SA=19.63\ m^{2}$

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

Find the cost of sphere with a 5.50-meter circumference

$9.73*(92)=\$895.16$

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Find the cost of sphere with a 7.85-meter circumference

$19.63*(92)=\$1,805.96$

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

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