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ryzh [129]
3 years ago
11

A square is cut diagonally into two equal parts. If each part has an area of 50 cm2, then what is the perimeter of each part?

Mathematics
1 answer:
statuscvo [17]3 years ago
6 0

Answer:

30cm

Step-by-step explanation:

Given data

When are square is cut diagonally into two parts

The resulting shape is a triangle

hence the area of the square = 50+50 = 100cm^2

The length of each side of the square = √100= 10cm

likewise the diagonal of the square = 10cm

Hence the perimeter of the resulting triangle= 10+10+10= 30cm

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The value of the 7 in 27,459 is how many times the value of the 7 in 40,735?
alukav5142 [94]

Answer:

10

Step-by-step explanation:

The 7 in 27,459 is in the <em>thousands</em> place.

The 7 in 40,735 is in the <em>hundreds</em> place.

Any digit in the thousands place has 10 times the value of the same digit in the hundreds place. (The multiplier is 1000, instead of 100.)

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In the base-10 number system, each digit location has 10 times the value of the location to its right. The value is determined by the place the digit occupies in the number. That is why it is called a place-value number system.

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3 years ago
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I need help with HW it is hard (repost i forgot picture)
creativ13 [48]

Answer:

b 8 hours

Step-by-step explanation:

1/4 is 2 so 2/4 is 4 and we know 3/4 is 6 so 4/4 is 8 which is the answer

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3 years ago
James states that quadrilateral
mr_godi [17]

Using the distance formula,

AD=\sqrt{(-1-3)^{2}+(-3-(-4))^{2}}=\sqrt{17}\\\\BC=\sqrt{(5-9)^{2}+(1-0)^{2}}=\sqrt{17} \\\\\therefore \overline{AD} \cong \overline{BC}

AB=\sqrt{(-1-5)^{2}+(-3-1)^{2}}=\sqrt{52}=2\sqrt{13}\\\\CD=\sqrt{(9-3)^{2}+(0-(-4))^{2}}=\sqrt{52}=2\sqrt{13}\\\\\therefore \overline{AB} \cong \overline{CD}

Since ABCD has two pairs of opposite congruent sides, it is a parallelogram.

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2 years ago
What is the answer to 125÷3​
Sunny_sXe [5.5K]

Answer:

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5 0
3 years ago
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15x^2 + 41x + 28 <br><br>STEP BY STEP ANSWER PLSSS​
maria [59]

Answer:

(3x+4)(5x+7)

Step-by-step explanation:

15x^2 +41x+28

Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2 +ax+bx+28. To find a and b, set up a system to be solved.

a+b=41

ab=15×28=420

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.

1,420

2,210

3,140

4,105

5,84

6,70

7,60

10,42

12,35

14,30

15,28

20,21

Calculate the sum for each pair.

1+420=421

2+210=212

3+140=143

4+105=109

5+84=89

6+70=76

7+60=67

10+42=52

12+35=47

14+30=44

15+28=43

20+21=41

The solution is the pair that gives sum 41.

a=20

b=21

Rewrite 15x^2 +41x+28 as (15x^2 +20x)+(21x+28).

(15x^2 +20x)+(21x+28)

Factor out 5x in the first and 7 in the second group.

5x(3x+4)+7(3x+4)

Factor out common term 3x+4 by using distributive property.

(3x+4)(5x+7)

7 0
3 years ago
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