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3 years ago

135pounds 5 months later 120 pounds find percent decrease

1 answer:

5 0

135 ----- 100%
120 ----- x
------------------------
x = 120*100/135 = 88,8

100-88,8 = 11,2 %

the decrease percent was 11,2 %

hope helped

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How long is the golden gate bridge?? above its 1

Oksanka [162]

If i've got the distance of the golden gate bridge right ,then it should be 20.88,you can round that up to either 20 or 21

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3 years ago

Is the relationship shown by the data linear? If so, model the data with an equation. x y –7 5 –5 9 –3 13 –1 17

diamong [38]

Given:

The table of values is:

x : -7 -5 -3 -1

y : 5 9 13 17

To find:

Whether the given data is linear and then find the equation.

Solution:

The given data is linear if the slope and rate of change is constant.

Slope formula:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Using the slope formula. we get

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Since the rate of change is constant, i.e., 2, therefore the given data is linear.

The slope of a linear equation is 2 and it passes through the point (-7,5). So, the equation of the line is:

$y-y_1=m(x-x_1)$

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$y-5=2(x+7)$

$y-5=2x+14$

Adding 5 on both sides, we get

$y-5+5=2x+14+5$

$y=2x+19$

Therefore, the equation for the given data is $y=2x+19$ .

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3 years ago

Diane keeps all of her toys on a shelf. The shelf is 24" long and 7" wide. If the wdith the shelf is doubled, what would happen

goblinko [34]

Step-by-step explanation:

Given that,

The length of the shelf = 24 inches

The width of the shelf = 7 inches

Area of the shelf, A = 24 × 7

= 168 inch²

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= 336 inch²

It means,

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3 years ago

Can someone help me with this question

Savatey [412]

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x^2 + 90.25 = 121

x^2 = 30.75

x^2 = $\sqrt{30.75}$

x = 5.54cm

rounded: 5.5cm

answer: D

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3 years ago

Tom throws a ball into the air. The ball travels on a parabolic path represented by the equation , where represents the height o

tigry1 [53]

Answer:

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Step-by-step explanation:

The equation is missing in the question.

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Now we know to reach its maximum height, h in t seconds, the derivative of h with respect to time t is given by :

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Now the differentiating the equation with respect to time t, we get

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