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Hoochie [10]
3 years ago
14

PLEASE HELP Is A'B'C'D' a translation, rotation, or reflection of ABCD? Explain how you can tell.

Mathematics
2 answers:
Serga [27]3 years ago
6 0

A’B’C’D’ is a reflection.

It is a reflection because it’s mirrored across the y-axis, like looking at the side of your face in the mirror. A translation is the same thing and moving it from one set of coords to another, without turning it. A rotation would be turning it, which A’B’C’D’ is neither of.

levacccp [35]3 years ago
3 0

Answer:

1. Is A'B'C'D' a translation, rotation, or reflection of ABCD? Explain how you can tell.

A'B'C'D' is a reflection over the y-axis. By flipping ABCD over the y-axis, the result will be A'B'C'D'

2. Is A"B"C"D" a translation, rotation, or reflection of A'B'C'D'? Explain.

A"B"C"D" is a rotation of A'B'C'D'. This is proven by the fact that if A'B'C'D' is rotated 90 degrees, the result will be A"B"C"D".

3. Suppose the measure of ∠B is 89°. Which other angles must measure 89°? How do you know?

If ∠B measures 89 degrees, then all other B angles must also measure 89 degrees because the angle is not changed by any of the transformations performed.

4. What is the perimeter of A"B"C"D"? Explain how you found the perimeter.

Because the size and shape are not any different from the original figure, the perimeter is 26.3 units.

6+6+6.3+8=26.3

Step-by-step explanation:

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180-115 = 65

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M is the midpoint of AN, A has coordinates
maksim [4K]

Step-by-step explanation:

According to Question , M is the midpoint of AN, A has coordinates (-7,4), and M has coordinates (-4, -1).

<u>Figure</u><u> </u><u>:</u><u>-</u>

\setlength{\unitlength}{1 cm}\begin{picture}(20,12) \put(4,0.2){\line(0,-1){0.4}}\put(1,0){\line(1,0){6}} \put(3.8,-0.6){$\bf M(-4,-1) $} \put(1,-0.6){$\bf A (-7,4)$}   \put(6.8,-0.6){$\bf N(x,y)$} \end{picture}

Let the coordinates of N be ( x , y )

Now , according to Midpoint Formula , the midpoint of points say A(x , y) and B (x' , y') is given by ,

\boxed{\blue{ \bf Midpoint =\bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) }}

<u>On</u><u> </u><u>using</u><u> </u><u>this</u><u> </u><u>formula</u><u> </u><u>,</u><u> </u>

=> Midpoint = \bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg)  \\ \\ => (-4, 1) = \bigg( \dfrac{x -7 }{2} , \dfrac{y + 4 }{2}\bigg) \\ \\ => -4 = \dfrac{x-7}{2} \\\\ => x - 7 = -8 \\\\ => x = 7 -8 \\\\ \boxed{\red{\sf=> x = -1 }} \\\\ => \dfrac{y+4}{2}=-1 \\\\=> y +4 = -2 \\ \\ y = -4-2 \\\\\boxed{\red{\sf=> y = -6 }}

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Equations
Vera_Pavlovna [14]

Step-by-step explanation:

I hope this is correct.

5 0
3 years ago
?????????????????????????????????????????????????????
Harrizon [31]

Answer:

9 yd

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A cube consists of 6 square faces.

Divide the surface area by 6 for the area of one face

486 ÷ 6 = 81 yd²

The area of a square is

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Here A = 81, then

s² = 81 ( take the square root of both sides )

s = \sqrt{81} = 9

Thus side length is 9 yd

7 0
3 years ago
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