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2 years ago

PLEASE HELP Is A'B'C'D' a translation, rotation, or reflection of ABCD? Explain how you can tell.

Mathematics

2 answers:

Serga [27]2 years ago

6 0

A’B’C’D’ is a reflection.

It is a reflection because it’s mirrored across the y-axis, like looking at the side of your face in the mirror. A translation is the same thing and moving it from one set of coords to another, without turning it. A rotation would be turning it, which A’B’C’D’ is neither of.

levacccp [35]2 years ago

3 0

Answer:

1. Is A'B'C'D' a translation, rotation, or reflection of ABCD? Explain how you can tell.

A'B'C'D' is a reflection over the y-axis. By flipping ABCD over the y-axis, the result will be A'B'C'D'

2. Is A"B"C"D" a translation, rotation, or reflection of A'B'C'D'? Explain.

A"B"C"D" is a rotation of A'B'C'D'. This is proven by the fact that if A'B'C'D' is rotated 90 degrees, the result will be A"B"C"D".

3. Suppose the measure of ∠B is 89°. Which other angles must measure 89°? How do you know?

If ∠B measures 89 degrees, then all other B angles must also measure 89 degrees because the angle is not changed by any of the transformations performed.

4. What is the perimeter of A"B"C"D"? Explain how you found the perimeter.

Because the size and shape are not any different from the original figure, the perimeter is 26.3 units.

6+6+6.3+8=26.3

Step-by-step explanation:

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MaRussiya [10]

Answer:

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2 years ago

Need help with 19-20 your suppose to simplify the expression

lesya692 [45]

To solve problem 19, we must remember the order of operations. PEMDAS tells us that we should simplify numbers in parentheses first, exponents next, multiplication and division after that, and finally addition and subtraction. Using this knowledge, we can begin to simplify the problem by working out the innermost set of parentheses:

36 / [10 - (3-1)²]

36 / [10 - (2)²]

Next, we should still simplify what is inside the parentheses but continue to solve the exponents (the next letter in PEMDAS).

36/ (10-4)

After that, we should compute the subtraction that is inside the parentheses.

36/6

Finally, we can solve using division.

Now, we can move onto problem 20:

1/4(16d - 24)

To solve this problem, we need to use the distributive property, which allows us to distribute the coefficient of 1/4 through the parentheses by multiplying each term by 1/4.

1/4 (16d-24)

1/4(16d) - 1/4(24)

Next, we can simplify further by using multiplication.

4d - 6

Therefore, your answer to problem 19 is 6 and the answer to problem 20 is 4d -6.

Hope this helps!

3 0

3 years ago

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BlackZzzverrR [31]

Answer:

Step-by-step explanation:

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6 0

3 years ago

Read 2 more answers

A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On

uysha [10]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

$h(x)=ax(x-7)$ ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

$4=a(3)((3)-7)$

$4=a(3)(-4)$

$\dfrac{4}{(3)(-4)}=a$

$-\dfrac{1}{3}=a$

Putting $a=-\dfrac{1}{3}$ , we get

$h(x)=-\dfrac{1}{3}x(x-7)$ ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

$h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)$

$h(1.5)=-(0.5)(-5.5)$

$h(1.5)=2.75$

Since h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

6 0

2 years ago

Prove that: 16sin20.sin40.sin60.sin80=3

olga nikolaevna [1]

to prove that 6720. Sin 40. Sin 60. 80 equals 3 you'd have to divide 16 by 20 multiply subtract both sides by 3 which is 24x + 6x + 8x + -14 equals 40 40 + 20 equals 16 - -40 equals 80 which equals to 3

6 0

3 years ago