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4 years ago

What is 2,541.7891 rounded to the nearest thosandth

Mathematics

1 answer:

astraxan [27]4 years ago

3 0

Answer:

3, 000

Step-by-step explanation:

+2, 500 rounds up

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The sides of the rectangle are in the ratio of 4:7. If its length is 31.5 in., find the width, the perimeter, and the area of th

AveGali [126]

Let $\ell$ the length and $w$ the width. By the ratio of the sides:

$\dfrac{w}{\ell}=\dfrac{4}{7}\Longrightarrow \dfrac{w}{31.5}=\dfrac{4}{7}\Longrightarrow w=\dfrac{4\cdot31.5}{7}\Longrightarrow \boxed{w=18~in.}$

Now, we'll find the perimeter p. We'll use the formula below:

$p=2(\ell+w)\\\\
p=2(31.5+18)\\\\
p=2\cdot49.5\\\\
\boxed{p=99~in.}$

The area of a rectangle is $S=w\cdot\ell$ . Then:

$S=w\cdot\ell\\\\
S=18\cdot31.5\\\\
\boxed{S=567~in.^2}$

8 0

4 years ago

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What is the total perimeter of this figure? Express your answer in feet.

bezimeni [28]

Answer:

i need to see the figure

Step-by-step explanation:

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4 years ago

The cost of ordering multiple items is sometimes, always or never proportional

AlladinOne [14]

Unless there is no promotion like "buy 2 get 1 free" or "buy 2 get 1 for 50%" etc. then the cost of ordering multiple items is always proportional. Let's say something costs $5. Two items will cost $10, three $15, four $20 etc. These numbers are all proportional. Hopefully that's what you meant :)

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4 years ago

17.6 degrees F<br> 35.2 degrees F<br> 41.0 degrees F<br> 72.2 degrees F

yaroslaw [1]

17.6 degrees I think

6 0

4 years ago

Please help me find out what the question marks are

quester [9]

Question a

g(x) times $\sqrt{x-5}=\sqrt{x^2-5}$
divide both sides by √(x-5)
$g(x)=\frac{\sqrt{x^2-5}}{\sqrt{x-5}}$
$g(x)=\frac{(\sqrt{x-5})(\sqrt{x^2-5})}{x-5}$
$g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}$

question b
$g(x) \space\ times \space\ 1+\frac{1}{x}=x$
divide both sides by 1+1/x
$g(x)=\frac{x}{1+\frac{1}{x}}$
times by x/x
$g(x)=\frac{x^2}{x+1}$

question c
$\frac{1}{x} \space\ times \space\ f(x)=x$
times both sides by x
$f(x)=x^2$

question d
the (f*g)(x) collumn seems to have a domain of only x is greater than or equal to 0?
so maybe we squared the whole thing, ya
wait
ah, ya
basically
$|x|=(\sqrt{x})^2=(\sqrt{x})(\sqrt{x})$
so f(x)=√x

a. $g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}$
b. $g(x)=\frac{x^2}{x+1}$
c. $f(x)=x^2$
d. $f(x)=\sqrt{x}$

3 0

4 years ago

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