All categories

3 years ago

I really need help. please help

1 answer:

7 0

I'm pretty sure the answer to A would be this: the common point that satisfies both equations (where they intersect) can be shown AS 4^(-x) = 8^(-x-1).

The answer to B is forming a table. This is quite easier than you think :D.

Start with x on one side (3) and go all the way down to -3 like this:

(x) 4^-x 8^-x-1
-3 64 (Do the same with this)
-2 16
-1 4
0 1
1 1/4
2 .0625
3 .015625

So basically you just fill in the x variable with every number between 3 and -3. After that, it's just a bit of math and you've done it!

C is a bit misguided. I think it would be quite simple to just use a graphing calculator, but you would have to actually input all the x and y values from the table. After that, you will have a graph.

I hope I helped! Good luck and good day!

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6x2-18x-60= What is the answer to the question

TiliK225 [7]

Answer:

1092

Step-by-step explanation:

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3 years ago

Read 2 more answers

HELP PLEASE I DONT UNDERSTAND AND NEED TO PASS

Nina [5.8K]

Answer:

20 for de first one and answer (B) for the second.

Step-by-step explanation:

20 for de first one and answer (B) for the second.

hope this helped;3

7 0

2 years ago

Find and interpret the mean absolute deviation of the data.

Zinaida [17]

Answer:

The mean absolute deviation is 4

Interpertation: The average distance between each data value and the mean is 4 which is the variation in the data set so you can understand how "spread out" each data point is from each other

Step-by-step explanation:

The mean absolute deviation is a measure of how much a data set varies.

<em>Step 1: Compute the mean</em>

mean = the sum of all the terms / number of terms

mean = 94 + 86 + 95 + 99 + 88 + 90 / 6

= 552 / 6

= 92

The mean is 92

<em>Step 2: Finding the absolute deviation</em>

You would take each number in the data set and subtract it from the mean, take the absolute value. After you take the sum of the absolute data values

= |94 - 92| + |86 - 92| + |95 - 92| + |99 - 92| + |88 - 92| + |90 - 92|

= |2| + |- 6| + |3| + |7| + |- 4| + |- 2|

= 2 + 6 + 3 + 7 + 4 + 2

= 24

To find the mean absolute deviation you divided the sum by total number of terms...

24/6 = 4

The average (mean) is equal to the sum of all the data values divided by the count of values in the data set (which was step 1)

Let me know if you have any questions !

I applied to be a live tutor, Hope to impove the experience :)

Have a nice day, feel free to give me feedback

3 0

2 years ago

Factor n(2n+3)+4(2n-3)

zavuch27 [327]

The answer would be 2n^2+3n+ 8n-1

3 0

2 years ago

You are a lifeguard and spot a drowning child 60 meters along the shore and 40 meters from the shore to the child. You run along

sukhopar [10]

Answer:

The lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

Step-by-step explanation:

This is a problem of optimization.

We have to minimize the time it takes for the lifeguard to reach the child.

The time can be calculated by dividing the distance by the speed for each section.

The distance in the shore and in the water depends on when the lifeguard gets in the water. We use the variable x to model this, as seen in the picture attached.

Then, the distance in the shore is d_b=x and the distance swimming can be calculated using the Pithagorean theorem:

$d_s^2=(60-x)^2+40^2=60^2-120x+x^2+40^2=x^2-120x+5200\\\\d_s=\sqrt{x^2-120x+5200}$

Then, the time (speed divided by distance) is:

$t=d_b/v_b+d_s/v_s\\\\t=x/4+\sqrt{x^2-120x+5200}/1.1$

To optimize this function we have to derive and equal to zero:

$\dfrac{dt}{dx}=\dfrac{1}{4}+\dfrac{1}{1.1}(\dfrac{1}{2})\dfrac{2x-120}{\sqrt{x^2-120x+5200}} \\\\\\\dfrac{dt}{dx}=\dfrac{1}{4} +\dfrac{1}{1.1} \dfrac{x-60}{\sqrt{x^2-120x+5200}} =0\\\\\\ \dfrac{x-60}{\sqrt{x^2-120x+5200}} =\dfrac{1.1}{4}=\dfrac{2}{7}\\\\\\ x-60=\dfrac{2}{7}\sqrt{x^2-120x+5200}\\\\\\(x-60)^2=\dfrac{2^2}{7^2}(x^2-120x+5200)\\\\\\(x-60)^2=\dfrac{4}{49}[(x-60)^2+40^2]\\\\\\(1-4/49)(x-60)^2=4*40^2/49=6400/49\\\\(45/49)(x-60)^2=6400/49\\\\45(x-60)^2=6400\\\\$

$x$

As $d_b=x$ , the lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

7 0

3 years ago