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miskamm [114]
3 years ago
5

If a single-celled organism is found to have a nucleus which contains its DNA and a phospholipid membrane, what else can safely

be assumed about it?
A. It is a member of the domain Eukaryota even though it cannot reproduce on its own.
B. It has mitochondria and is a member of the domain Eukaryota.
C. It has a cell wall and can photosynthesize and could belong to the domain Bacteria.
D. It has no other organelles besides the nucleus and is a member of the domain Bacteria.
Biology
2 answers:
zloy xaker [14]3 years ago
5 0

Answer:

B. It has mitochondria and is a member of the domain Eukaryota.

Explanation:

Eukaryota cells can form snglie celled or multicelled organisms, but what makes them Eukaryota is the fact that they have a nucleus where they store all of the DNA of that cell, it also means that if it  is a Eukaryota cell it has to have a mitochondria to carry out the functions of energy conversion in the cell, so the best option would be B. It has mitochondria and is a member of the domain Eukaryota.

makkiz [27]3 years ago
3 0
It would be D. i belive 

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When the patch occupancy rate (c) equals the patch extinction rate (e), patch occupancy (P) is
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Answer:

When the patch occupancy rate (c) equals the patch extinction rate (e), patch occupancy (P) is 0

Explanation:

According to Levin's model (1969):

<em>dP/dt = c - e</em>

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<em>c</em><em> </em>and <em>e </em>are the local immigration and extinction probabilities per patch.

Thus, the rate of change of P, written as dP/dt, tells you whether P will increase, decrease or stay the same:

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The rate dP/dt is calculated by the difference between colonization or occupancy rate (<em>c</em>) and extinction rate (<em>e</em>).

c is then calculated as the number of successful colonizations of unoccupied patches as a proportion of all available patches, while e is the proportion of patches becoming empty. Notice that P can range between 0  and  1.

As a result, if the patch occupancy rate (c) equals the patch extinction rate (e), then patch occupancy P equals to 0.

7 0
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Answer:

<h2>B) 4, 6, 7, 1, 2, 3, 5</h2>

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<h3>Define adaptation?</h3>

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