x = [-(-6) +/- sqrt((-6)^2 - 4*1 * 8))] / 2
= (6 + sqrt4) / 2 , ( 6 - sqrt4)/2
= 4 , 2
Answer:
Probability that they are the youngest is 0.000549
Step-by-step explanation:
Given
Number of students = 16
Selected students = 4
Let n = number of students
n = 16
Let r = selections
r = 4
We're interested in selecting 4 students out of 16; the keyword, selection means we're dealing with combination because order is not important.
So,
Solving for nCr
nCr = n!/((n-r)!r!)
16C4 = 16!/((16-4)!4!)
16C4 = 16!/(12!4!)
16C4 = 16 * 15 * 14 * 13 * 12!/(12!4!)
16C4 = 16 * 15 * 14 * 13 / 4 * 3 * 2 * 1
16C4 = 1820 ways
There are 1820 ways of selecting 4 students from a total of 1820.
Only one of these ways can the four of them be the youngest.
So, probability = 1/1820
Probability = 0.0005494506
Probability that they are the youngest is 0.000549 (approximately)
it is B because you add the fractions together first then the other numbers then you get B
Answer:
but i would say t t f t
Step-by-step explanation:
Are u wrong or right
