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sergiy2304 [10]
3 years ago
11

|2x| ≤ x + 3

Mathematics
2 answers:
Korolek [52]3 years ago
5 0

Let's solve your inequality step-by-step.

|2x|≤x+3

Solve Absolute Value.

|2x|≤x+3

Let's find the critical points of the inequality.

|2x|=x+3

We know either2x=x+3or2x=−(x+3)

2x=x+3(Possibility 1)

2x−x=x+3−x(Subtract x from both sides)

x=3

2x=−(x+3)(Possibility 2)

2x=−x−3(Simplify both sides of the equation)

2x+x=−x−3+x(Add x to both sides)

3x=−3

3x

3

=

−3

3

(Divide both sides by 3)

x=−1

Check possible critical points.

x=3(Works in original equation)

x=−1(Works in original equation)

Critical points:

x=3 or x=−1

Check intervals in between critical points. (Test values in the intervals to see if they work.)

x≤−1(Doesn't work in original inequality)

−1≤x≤3(Works in original inequality)

x≥3(Doesn't work in original inequality)

Answer:

−1≤x≤3

r-ruslan [8.4K]3 years ago
3 0

Answer:

[-1,3]

Step-by-step explanation:

|2x|<x+3

calculate the absolute value

2*|x|<x+3

move < to left

2*|x|-x<3

split into possible cases

2x-x<3, x<0

2*(-x)-x<3, x<0

solve inequalities

[0,3]

[-1,0]

find union

[-1,3]

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Can y’all help me pls
bija089 [108]

Answer:

The answer is (1,-9)

Step-by-step explanation:

First, you have to plug -9x to y because y = -9x. Then multiply

-6(-9x) = 54x

-8x + 54x = 46

46x = 46

x = 1

Plug 1 into the first equation to find the value of y.

y = -9(1)

y= -9

7 0
3 years ago
If a normal distribution has a mean of 44 and a standard deviation of 8, what
Luda [366]

Answer:

The answer to this question is gotta be 0

Step-by-step explanation:

Because a normal distribution gives an area between 0 and z and the area for P(X=46) = 0

5 0
3 years ago
Solve for the variable: 6/25 = d/30
pentagon [3]

Answer:

d = 7.2

Step-by-step explanation:

We can cross multiply the equation to get:

6 * 30 = 25 * d

(* is multiplication sign by the way)

180 = 25d

Divide both sides by 25 to get:

d = 7.2

3 0
3 years ago
Conditional Probability Assistance?
krek1111 [17]

Let the event A=\{ Sophomore \}, B=\{ Boy \}

The the probability of the events

P(A \cap B)=\frac{5}{12+18} =\frac{1}{6}

P( B)=\frac{12}{12+18} =\frac{2}{5}

The conditional probability

P(Sophomore|Boy)=P(A|B)=\frac{P(A \cap B)}{P(B)} =\frac{1/6}{2/5} =\frac{5}{12}

5 0
3 years ago
Nvm bro i got the answer
KIM [24]
Ok and have a nice day
6 0
2 years ago
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