Answer:
overstated
Explanation:
Adjusting entry is a term used in the accounting process, which describes journal entries usually carried out at the end of an accounting period to assign income and expenditure to the period in which they actually happened.
However, the journal entry to identify a deferred revenue is to debit or increase cash and credit or increase a deposit or another liability account.
Hence, Failure to record the adjusting entry for deferred revenue now earned causes liabilities on the balance sheet to be what OVERSTATED
Answer:
$1,138.92
Explanation:
Current bond price can be calculated present value (PV) of cash flows formula below:
Current price or PV of bond = C{[1 - (1 + i)^-n] ÷ i} + {M × (1 + i)^-n} ...... (1)
Where:
Face value = $1,000
r = coupon rate = 7.2% annually = (7.2% ÷ 2) semiannually = 3.6% semiannually
C = Amount of semiannual interest payment = Face value × r
C = $1,000 × 3.6% = $36
n = number of payment periods remaining = (12 - 1) × 2 = 22
i = YTM = 5.5% annually = (5.5% ÷ 2) semiannually = 2.75% semiannually = 0.0275 semiannually
M = value at maturity = face value = $1,000
Substituting the values into equation (1), we have:
PV of bond = 36{[1 - (1 + 0.0275)^-22] ÷ 0.0275} + {1,000 × (1 + 0.0275)^-22}
PV of bond = $1,138.92.
Therefore, the current bond price is $1,138.92.
Answer:
Year Cashflow [email protected]% PV
$ $
0 (750,000) 1 (750,000)
1 350,000 0.9259 324,065
2 325,000 0.8573 278,623
3 250,000 0.7938 198.450
4 180,000 0.7350 132,300
NPV 184,438
The correct answer is D. The difference in answers is due to rounding error.
Explanation:
Net present value is the diffrence between initial outlay and present value of inflow. We need to discount the cash inflows for year 1 to year 4 at 8% and then calculate the present value of cash inflows by multiplying the cash inflows by the discount factors. Finally, we will calculate NPV by deducting the initial outlay from the present value of cash inflows.
Answer:
have developed through to the performing stage
Answer:
EV of node 4 = 0.6×5 + 0.4×0 = 3
EV of node 5 = 0.1×5 + 0.9×0 = 0.5
EV of node 2 = (0.8×5 + 0.2×EV of node 4) - 3
EV of node 2 = (0.8×5 + 0.2×3 ) - 3
EV of node 2 = 4.6 - 3
EV of node 2 = 1.6
EV of node 3 = (0.5×5 + 0.5×EV of node 5) - 1
EV of node 3 = (0.5×5 + 0.5×0.5 ) - 1
EV of node 3 = 2.75 - 1
EV of node 3 = 1.75
EV of node 3 is higher, therefore, best attend pattern is to attend randomly.
