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Leokris [45]
3 years ago
6

The revenue from selling x shirts is r(x) = 11x.

Mathematics
1 answer:
maria [59]3 years ago
8 0

Answer:

Correct answer is: D p(x)=5x-20: Apex

Step-by-step explanation:


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5 milligrams are equal to .005 grams.

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Do 1/4 and 4/16 form a proportion
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yes, a 1:1 proportion

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Which statement is true?
g100num [7]
A is the answer to the equation
6 0
3 years ago
Solve this system of linear equations. separate the x- and y- values with a coma. -12x=-75-11y
ycow [4]
Solve the following system:
{-12 x = -11 y - 75 | (equation 1)
{-5 x = -11 y - 89 | (equation 2)
Express the system in standard form:
{-(12 x) + 11 y = -75 | (equation 1)
{-(5 x) + 11 y = -89 | (equation 2)
Subtract 5/12 × (equation 1) from equation 2:
{-(12 x) + 11 y = -75 | (equation 1)
{0 x+(77 y)/12 = (-231)/4 | (equation 2)
Multiply equation 2 by 12/77:
{-(12 x) + 11 y = -75 | (equation 1)
{0 x+y = -9 | (equation 2)
Subtract 11 × (equation 2) from equation 1:
{-(12 x)+0 y = 24 | (equation 1)
{0 x+y = -9 | (equation 2)

Divide equation 1 by -12:
{x+0 y = -2 | (equation 1)
{0 x+y = -9 | (equation 2)
Collect results:
Answer:  {x = -2                {y = -9

please note that the parentheses "{" should span over both equations but the editor doesn't allow that so I should it on both line, See attached example.










4 0
3 years ago
Find the coordinates of the other endpoint of the​ segment, given its midpoint and one endpoint.​ (Hint: Let​ (x,y) be the unkno
makkiz [27]

Step-by-step explanation:

Hey, there!!

Here, one point is A(10,8) and P(8,5) is the midpoint.

Let B(x,y) be the another end point.

Now,

Using midpoint formulae,

p(x.y) =  \frac{x1 + x2}{2} . \frac{y1 + y2}{2}

p(8.5) = ( \frac{10 + x}{2} . \frac{8 + y}{2} )

Since they are equal,equating with their corresponding elements we get,

8 =  \frac{10 + x}{2}

or, 16 = 10 + x

or, x=16-10

Therefore, x = 6

Now,

5 =  \frac{8 + y}{2}

or, 10 = 8 + y

or, y = 2

Therefore, The coordinates of another point are B(6,2)

<em><u>Hope it helps</u></em><em><u> </u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

8 0
4 years ago
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