The revenue from selling x shirts is r(x) = 11x.

There are 10 kids in class. 7 boys and 3 girls. If the teacher were to pick 4 students at random what is the probability of sele

inysia [295]

Well there are 7 boys and 10 students total so 7/10=0.7=70%. Therefore there is a 70% chance.

4 0

4 years ago

PLEASE HELP

kicyunya [14]

Y= k x 2x so when x=6 and y=72, we find k= 6 so when x=4 we get (12) x 2(4) and find y=96 :)

4 0

3 years ago

The equation x^2 + y^2 + 21 = 40 + 18y. What is the radius of this cookie?

trapecia [35]

Answer:

The radius is 10

Step-by-step explanation:

Given

$x^2 + y^2 + 21 = 40 + 18y.$

Required

The radius

Rewrite as:

$x^2 + y^2 - 18y = 40-21$

Subtract 81 from both sides

$x^2 + y^2 - 18y +81= 40-21+81$

Expand

$x^2 + y^2 - 9y - 9y +81= 40-21+81$

Factorize

$x^2 + y( y- 9) - 9(y -9)= 40-21+81$

Factor out y - 9

$x^2 + (y- 9) (y -9)= 40-21+81$

Express as squares

$x^2 + (y- 9)^2= 100$

$x^2 + (y- 9)= 10^2$

The equation of a circle is:

$(x - a)^2 + (y- b)= r^2$

By comparison:

$r^2=10^2$

$r = 10$

6 0

3 years ago

Create an equation of a line that crosses the y-axis at the origin and has a slope of 1/2

Salsk061 [2.6K]

Answer:

since the line goes through the origin you dont need a y intercept.

y= x/2

or y= 1/2 x

8 0

3 years ago

"Durable press" cotton fabrics are treated to improve their recovery from wrinkles after washing "Wrinkle recovery angle" measur

ludmilkaskok [199]

Answer:

At 5% there is significant evidence to reject the null hypothesis. You can conclude that there is a difference between the population mean of the wrinkle recovery angle of fabric treated with Permafresh and the population mean of the wrinkle recovery angle of fabric treated with Hylite.

a)

X[bar]₁= 120.8 degrees

X[bar]₂= 162.75 degrees

b)

S₁²= 14.5155 degrees

S₂²= 24.4727 degrees

Step-by-step explanation:

Hello!

The study variable is X: wrinkle recovery angle for a fabric specimen.

There is a suspicion that there is a difference in recovery from wrinkles after washing between two products (Permafresh and Hilite). To test this suspicion two random samples of fabric, 5 were treated with Permafresh and 4 were treated with Hylite resulting in the data:

Sample 1 (Permafresh)

X₁: wrinkle recovery angle for a fabric specimen treated with Permafresh.

X₁~N(μ₁;σ₁²)

n₁= 5

124; 104; 142; 111; 123

Sample mean X[bar]₁= (∑x₁i)/n₁= 604/5= 120.8 degrees

Sample variance S₁²= $\frac{1}{(n₁-1)}$ [(∑x₁²i)-(∑x₁i)²/n₁] = $\frac{1}{4}$ [(73806)-(604)²/5]= 210.7 degrees²

S₁= 14.515 ≅ 14.52 degrees

Sample 2 (Hylite)

X₂: wrinkle recovery angre for a fabric specimen trated with Hylite.

X₂~N(μ₂;σ₂²)

n₂= 4

147; 199; 149; 156

Sample mean X[bar]₂= (∑x₂i)/n₂= 651/4= 162.75 degrees

Sample variance S₂²= $\frac{1}{(n₂-1)}$ [(∑x₂²i)-(∑x₂i)²/n₂] = $\frac{1}{3}$ [(107747)-(651)²/4]= 598.916 ≅ 598.92 degrees²

S₂= 24.472≅ 24.47 degrees

To test the suspicion that there is a difference between the winkle recovery angle on fabric samples treated with Permafresh and Hylite, the hypothesis is:

H₀: μ₁ = μ₂

H₁: μ₁ ≠ μ₂

α: 0.05

To test the difference between the population means, considering that only sample information is available and the size of both samples, the most appropriate statistic to use is a pooled t for independent samples (unknown but equal population variances):

t= (X[bar]₁ - X[bar]₂) - (μ₁ - μ₂) ~t $_{n_1+n_2-2}$

Sa√(1/n₁+1/n₂)

Sa²= (n₁-1)S₁² + (n₂-1)S₂² = (4*210.7)+(3*598.92) = 377.08

n₁ + n₂ - 2 5+4-2

Sa= 19.418≅ 19.42

t= (X[bar]₁ - X[bar]₂) - (μ₁ - μ₂) = (120.8-162.75) - 0 = -3.22

Sa√(1/n₁+1/n₂) 19.42√(1/5+1/4)

Using the critical region approach, this rejection region is two-tailed with critical values:

$t_{n_1+n_2-2; \alpha/2 } = t_{7; 0.025 } = -2.365$

$t_{n_1+n_2-2; 1- \alpha/2 } = t_{7; 0.975 } = 2.365$

If t ≤ -2.365 or t ≥2.365, then the decision is to reject the null hypothesis.

If -2.365 < t < 2.365, then the decision is to not reject the null hypothesis.

Since the calculated t-value is less than the left critical value, the decision is to reject the null hypothesis.

I've calculated the p-value for the test: 0.0146

This p-value is less than the significance level of 0.05, then, using this approach, the decision is also to reject the null hypothesis.

This means, that at 5% there is significant evidence to reject the null hypothesis. You can conclude that there is a difference between the population mean of the wrinkle recovery angle of fabric treated with Permafresh and the population mean of the wrinkle recovery angle of fabric treated with Hylite.

I hope it helps!

4 0

4 years ago