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Simora [160]
2 years ago
12

Point M(5, 2) is the midpoint of segment XY. Point X has coordinates

Mathematics
2 answers:
viva [34]2 years ago
6 0

Answer:

Y (14, - 2 )

Step-by-step explanation:

using the midpoint formula for (x₁, y₁ ) and (x₂, y₂ ) , then

midpoint = ( \frac{x_{1}+x_{2}  }{2} , \frac{y_{1+y_{2} } }{2} )

equating the x- coordinates and the y- coordinates

let coordinates of Y = (x, y )

\frac{x-4}{2} = 5 ( multiply both sides by 2 )

x - 4 = 10 ( add 4 to both sides )

x = 14

and

\frac{y+6}{2} = 2 ( multiply both sides by 2 )

y + 6 = 4 ( subtract 6 from both sides )

y = - 2

coordinates of Y = (14, - 2 )

RideAnS [48]2 years ago
4 0

Answer:

(14, -2)

Step-by-step explanation:

The coordinates of the midpoint is equal to the mean of the coordinates of the endpoints.

=============================================================

Solving :

⇒ 5 = -4 + x / 2

⇒ x - 4 = 10

⇒ <u>x = 14</u>

⇒ 2 = 6 + y / 2

⇒ y + 6 = 4

⇒ <u>y = -2</u>

===========================================================

Coordinates of Point Y :

⇒ Y = (x, y)

⇒ Y = (14, -2)

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Answer:

Step-by-step explanation:

32n($1.75/n)=$56

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How can you tell if two equations for parallel lines or perpendicular lines. please explain?
kicyunya [14]
To find out if they are parallel we need to see if the gradient is the same, to do this we need to get y in terms of x:
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The gradient is the coefficient of x (the number infront of x)
For equation 1 the gradient is -1, and for number 2 it is 1, therefore they are not parallel.
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Alex Ar [27]

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12

Step-by-step explanation:

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8 0
3 years ago
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A carpenter is building a rectangular shed with a fixed perimeter of 54 ft. What are the dimensions of the largest shed that can
lutik1710 [3]

Answer:

the Largest shed dimension is 13.5 ft by 13.5 ft

Largest Area is 182.25 ft²

Step-by-step explanation:

Given that;

Perimeter = 54 ft

P = 2( L + B ) = 54ft

L + B = 54/2

L + B = 27 ft

B = 27 - L ------------Let this be equation 1

Area A = L × B

from equ 1, B = 27 - L

Area A = L × ( 27 - L)

A = 27L - L²

for Maxima or Minima

dA/dL = 0

27 - 2L = 0

27 = 2L

L = 13.5 ft

Now, d²A/dL² = -2 < 0

That is, area is maximum at L = 13.5 using second derivative test

B = 27 - L

we substitute vale of L

B = 27 - 13.5 = 13.5 ft

Therefore the Largest shed dimension = 13.5 ft by 13.5 ft

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7 0
2 years ago
I need help with this one please
skelet666 [1.2K]

Answer:

perimeter of figure = 24.28

Step-by-step explanation:

semicircle ' s perimeter = π r = 3.14 × 2 = 6.28 cm

perimeter of 3 sides of parallelogram = 7 +7+4= 18 cm.

perimeter of figure = 18 +6.28 = 24.28

approx value = 24.30 cm

3 0
2 years ago
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