If it was 25%, it would be a 90 degree angle. So we can calculate this using a proportion. 25/90 = 24/x. Cross multiply to get 25x = 2160. When you divide by 25 on both sides you get 86.4. So the angle should be 86 degrees. Hope this helps.
Answer:
203 feet.
Step-by-step explanation:
Please find the attachment.
Let h represent the height of the building.
We have been given that at 3:30 in the afternoon in mid-September the Kimball Tower casts a shadow about 290 feet long when the sun's rays come down at an angle about 35 degrees above the horizontal.
We know that tangent relates opposite side of a right triangle to its adjacent side.
![\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}](https://tex.z-dn.net/?f=%5Ctext%7Btan%7D%3D%5Cfrac%7B%5Ctext%7BOpposite%7D%7D%7B%5Ctext%7BAdjacent%7D%7D)
Upon substituting our given values in above formula, we will get:
![\text{tan}(35^{\circ})=\frac{h}{290}](https://tex.z-dn.net/?f=%5Ctext%7Btan%7D%2835%5E%7B%5Ccirc%7D%29%3D%5Cfrac%7Bh%7D%7B290%7D)
![290*\text{tan}(35^{\circ})=\frac{h}{290}*290](https://tex.z-dn.net/?f=290%2A%5Ctext%7Btan%7D%2835%5E%7B%5Ccirc%7D%29%3D%5Cfrac%7Bh%7D%7B290%7D%2A290)
![290*0.70020753821=h](https://tex.z-dn.net/?f=290%2A0.70020753821%3Dh)
![h=290*0.70020753821](https://tex.z-dn.net/?f=h%3D290%2A0.70020753821)
![h=203.0601860809](https://tex.z-dn.net/?f=h%3D203.0601860809)
![h\approx 203](https://tex.z-dn.net/?f=h%5Capprox%20203)
Therefore, the building is approximately 203 feet high.
The other dog's age is "x". Rex's puppy is 5 years less than "x". SO...
x-5.
Understand?
we know that
In the right triangle ABC
∠
∠
------> by complementary angles
so
Step ![1](https://tex.z-dn.net/?f=%201%20)
Find the measure of angle B
we know that
![tan\ B=\frac{opposite\ side\ angle\ B}{adjacent\ side\ angle\ B}](https://tex.z-dn.net/?f=%20tan%5C%20%20B%3D%5Cfrac%7Bopposite%5C%20%20side%5C%20%20angle%5C%20%20B%7D%7Badjacent%5C%20%20side%5C%20%20angle%5C%20%20B%7D%20%20)
in this problem
![opposite\ side\ angle\ B=7in\\ adjacent\ side\ angle\ B=5in](https://tex.z-dn.net/?f=%20opposite%5C%20%20side%5C%20%20angle%5C%20%20B%3D7in%5C%5C%20adjacent%5C%20%20side%5C%20%20angle%5C%20%20B%3D5in%20)
so
![tan\ B=\frac{7}{5} \\ \\ B=arc\ tan\frac{7}{5} \\ \\ B=54.5\ degrees](https://tex.z-dn.net/?f=%20tan%5C%20%20B%3D%5Cfrac%7B7%7D%7B5%7D%20%5C%5C%20%5C%5C%20B%3Darc%5C%20tan%5Cfrac%7B7%7D%7B5%7D%20%5C%5C%20%5C%5C%20B%3D54.5%5C%20degrees%20)
Step ![2](https://tex.z-dn.net/?f=%202%20)
Find the measure of angle A
![A+B=90\\ A=90-B\\ A=90-54.5\\ A=35.5\ degrees](https://tex.z-dn.net/?f=%20A%2BB%3D90%5C%5C%20A%3D90-B%5C%5C%20A%3D90-54.5%5C%5C%20A%3D35.5%5C%20degrees%20)
therefore
the answer is the option
35.5° and 54.5°
x² + 10x = 26
x² + 10x + 25 = 26 + 25
x² + 5x + 5x + 25 = 51
x(x) + x(5) + 5(x) + 5(5) = 51
x(x + 5) + 5(x + 5) = 51
(x + 5)(x + 5) = 51
(x + 5)² = 51
x + 5 = ±√(51)
- 5 - 5
x = -5 ± √(51)
x = -5 + √(51) or x = -5 - √(51)