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Papessa [141]
3 years ago
12

A line passes through the point (-3, -3) and has a slope of 1/2. What is the equation of the line?

Mathematics
1 answer:
harina [27]3 years ago
8 0
To solve this, we need to understand Slope Intercept Form (SIF), as well as how to graph a line.

SIF is the standard equation of lines on graphs. It is "y=mx+b" where m is the slope and b is the y-intercept. The y-intercept is the value of y when x is 0.

To find the y-intercept (which we will need to form the equation), we should simply graph the line. This will let us visualize the y-intercept, and overall make it easier to understand.

To graph a line, we should start with the point we have (that being (3, 3)) and follow the slope with rise/run. This means in this case, we will go right 2 for every 1 up, or 2 left for every 1 down.

Below I have attached a graph to help you see how to graph this, which we will get our equation from. The highlighted area is our y-intercept. The red circle shows our original point (3,3), and the blue dots show our slope.

Using the graph, we can see the equation for this line is y=1/2x+1.5.

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Factor 64b-16c to identify the equivalent expressions.
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How many feet of fencing are needed to enclose the garden? 54 feet 68 feet 108 feet 140 feet.
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A bucket contains 10 balls numbered as follows: 1, 2, 2, 3, 3, 3, 3, 4,4,5.
gladu [14]

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30% chance or \frac{3}{10}

Step-by-step explanation:

1, 2, 2, 3, 3, 3, 3, 4, 4, 5

The only numbers above 3 is 4, 4, and 5. There are 3 numbers greater than 3 and there are 10 total numbers, so the chance is \frac{3}{10} theoretical chance of getting a number GREATER than 3 or 30% chance.

8 0
3 years ago
For what values of θ is sinθ < cosθ when 0 ≤ θ < π ?
zysi [14]
<h3>Answer:  0 \le \theta < \frac{\pi}{4}</h3>

=========================================================

How to get this answer:

Use the unit circle to note that \sin\theta = \cos\theta = \frac{\sqrt{2}}{2} when \theta = \frac{\pi}{4} (aka 45 degrees)

Beyond this point, cosine is smaller than sine. This means that anything from 0 to pi/4 will have sine be smaller than cosine. It might help to graph y = sin(x) and y = cos(x) on the interval from x = 0 to x = pi.

The two curves y = sin(x) and y = cos(x) intersect at the point \left(\frac{\pi}{4}, \frac{\sqrt{2}}{2}\right)

-------------------------------

Here's a more detailed picture of whats going on.

\sin \theta < \cos \theta\\\\\sin \theta < \sqrt{1-\sin^2\theta}\\\\\sin^2 \theta < 1-\sin^2\theta \\\\2\sin^2 \theta < 1\\\\\sin^2 \theta < \frac{1}{2}\\\\\sin \theta < \sqrt{\frac{1}{2}}\\\\\sin \theta < \frac{1}{\sqrt{2}}\\\\\sin \theta < \frac{\sqrt{2}}{2}\\\\\theta < \arcsin\left(\frac{\sqrt{2}}{2}\right)\\\\\theta < \frac{\pi}{4}\\\\

Intersect the intervals 0 \le \theta < \pi and \theta < \frac{\pi}{4} and you'll end up with the final answer 0 \le \theta < \frac{\pi}{4}

4 0
3 years ago
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