Find the critical points of f(y):Compute the critical points of -5 y^2
To find all critical points, first compute f'(y):( d)/( dy)(-5 y^2) = -10 y:f'(y) = -10 y
Solving -10 y = 0 yields y = 0:y = 0
f'(y) exists everywhere:-10 y exists everywhere
The only critical point of -5 y^2 is at y = 0:y = 0
The domain of -5 y^2 is R:The endpoints of R are y = -∞ and ∞
Evaluate -5 y^2 at y = -∞, 0 and ∞:The open endpoints of the domain are marked in grayy | f(y)-∞ | -∞0 | 0∞ | -∞
The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:The open endpoints of the domain are marked in grayy | f(y) | extrema type-∞ | -∞ | global min0 | 0 | global max∞ | -∞ | global min
Remove the points y = -∞ and ∞ from the tableThese cannot be global extrema, as the value of f(y) here is never achieved:y | f(y) | extrema type0 | 0 | global max
f(y) = -5 y^2 has one global maximum:Answer: f(y) has a global maximum at y = 0
Answer:
The equation that represents the population after T years is
![P_{t} = 7,632,819,325 [1 +\frac{1.09}{100} ]^{T}](https://tex.z-dn.net/?f=P_%7Bt%7D%20%20%3D%207%2C632%2C819%2C325%20%5B1%20%2B%5Cfrac%7B1.09%7D%7B100%7D%20%5D%5E%7BT%7D)
Step-by-step explanation:
Population in the year 2018 ( P )= 7,632,819,325
Rate of increase R = 1.09 %
The population after T years is given by the formula
-------- (1)
Where P = population in 2018
R = rate of increase
T = time period
Put the values of P & R in above equation we get
![P_{t} = 7,632,819,325 [1 +\frac{1.09}{100} ]^{T}](https://tex.z-dn.net/?f=P_%7Bt%7D%20%20%3D%207%2C632%2C819%2C325%20%5B1%20%2B%5Cfrac%7B1.09%7D%7B100%7D%20%5D%5E%7BT%7D)
This is the equation that represents the population after T years.
Answer:
a. 14,000
b. 140,000
Step-by-step explanation:
Answer:
Let's calculate:
22-5
• Remove minus in the exponent and invert the base:
= (1/22)5
• Expand the multiplication:
= (1/22) * (1/22) * (1/22) * (1/22) * (1/22)
• Find your result:
= 1/5153632 ≈ 0.000000194038